Question

我有一个电子邮件列，连续存储至少10封以上的电子邮件。现在，我想写一个查询，将每封电子邮件放在一个单独的行上，例如：

   hay@line.com
   u@y.com
   live.gmail.com

如何写这个？

Answer 1

如果您的意思是数据行...如果您没有2016年，任何解析/拆分功能都会执行。否则，REPLACE（）就像JohnHC所提到的那样

Declare @YourTable table (ID int,Emails varchar(max))
Insert Into @YourTable values
(1,'hay@line.com,u@y.com,live.gmail.com')

Select A.ID
      ,EMail=B.RetVal
 From  @YourTable A
 Cross Apply [dbo].[udf-Str-Parse](A.EMails,',') B

返回

ID  EMail
1   hay@line.com
1   u@y.com
1   live.gmail.com

或者只是

Select * from [dbo].[udf-Str-Parse]('hay@line.com,u@y.com,live.gmail.com',',')

返回

RetSeq  RetVal
1       hay@line.com
2       u@y.com
3       live.gmail.com

需要的功能

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimiter varchar(10))
Returns Table 
As
Return (  
    Select RetSeq = Row_Number() over (Order By (Select null))
          ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
    From (Select x = Cast('<x>'+ Replace(@String,@Delimiter,'</x><x>')+'</x>' as xml).query('.')) as A 
    Cross Apply x.nodes('x') AS B(i)
);
--Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ')

Answer 2

使用Replace()

select replace(MyEmailField, '<CurrentDelimeter>', char(13)) as NewEmail
from MyTable

在Sql中的分隔字段中换行或回车

2 个答案: