Question

我有MySQL数据库的备份，备份文件的名称中包含时间和日期，如下所示：

daily_amavisd_2016-10-01_05h28m_Saturday.sql.gz 
daily_amavisd_2016-10-02_05h28m_Sunday.sql.gz 
daily_amavisd_2016-10-03_05h28m_Monday.sql.gz

我需要一个脚本来检查文件夹/backup/amavisd/daily中的最旧文件是否不超过一周。如果它超过一周，它应该给我状态"backup failed"，如果它不超过一周，它应该给我状态"backup OK"。

有人可以帮助我使用shell脚本吗？

Answer 1

如果你想打印文件名和状态，这可以帮到你;

#!/bin/bash

find /backup/amavisd/daily/ -name '*.gz' -exec bash -c '
file_date=$(echo $1|cut -f 3 -d '_');
start_date=$(date +"%Y-%m-%d" -d "-7 days");
    if [[ "$file_date" > "$start_date" ]]; then
        echo "$1: backup OK"
    else
        echo "$1: backup failed"
    fi' -- {} \;

例如

user@host:/tmp/test$ ./test.sh
backup/amavisd/daily/daily_amavisd_2016-10-01_05h28m_Saturday.sql.gz: backup OK
backup/amavisd/daily/daily_amavisd_2016-10-03_05h28m_Monday.sql.gz: backup OK
backup/amavisd/daily/daily_amavisd_2016-10-02_05h28m_Sunday.sql.gz: backup OK
backup/amavisd/daily/daily_amavisd_2016-10-07_05h28m_Monday.sql.gz: backup OK
backup/amavisd/daily/daily_amavisd_2016-09-07_05h28m_Monday.sql.gz: backup failed

Linux shell脚本用于超过一定时间的文件

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