我有以下php服务器代码:
$xml ="<?xml version=\"1.0\" encoding=\"UTF-8\"?>";
$root = "Data";
$warmdata = "WarmData";
$brinedata = "BrineData";
$permindata = "PerMinData";
$xml .= "<$root>";
$xml .= "<$warmdata>";
foreach($result as $row)
{
$xml .= "<WarmIn>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</WarmIn>";
}
foreach($result2 as $row)
{
$xml .= "<WarmOut>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</WarmOut>";
}
$xml .= "</$warmdata>";
$xml .= "<$brinedata>";
foreach($result3 as $row)
{
$xml .= "<BrineIn>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</BrineIn>";
}
foreach($result4 as $row)
{
$xml .= "<BrineOut>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</BrineOut>";
}
$xml .= "</$brinedata>";
$xml .= "<$permindata>";
foreach($result5 as $row)
{
$xml .= "<WarmPerMin>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</WarmPerMin>";
}
foreach($result6 as $row)
{
$xml .= "<BrinePerMin>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</BrinePerMin>";
}
$xml .= "</$permindata>";
$xml .= "</$root>";
header ("Content-Type:text/xml");
return $xml;
$options=array('uri'=>'http://localhost/');
$server = new SoapServer(NULL,$options);
$server->setClass('DBData');
$server->handle();
我正在尝试使用soap客户端获取格式正确的xml输出,但是当我请求xml时,out只包含从单个数据库中检索到的数字,而不包含实际的xml标记。 我怎么能修改它所以我会在输出中有标签?
答案 0 :(得分:1)
不允许使用这些标签。你必须写下来:
< replace with >
> replace with <