Question

所以我需要通过单击jsp中的按钮来执行unix命令。

这是jsp：

<body>
    <div align="center">
    <h2>Welcome to ETL Automation Testing Tool</h2>
    <h3>Please select Graph:</h3>
    <table border="1">
    <th>Graph</th>

    <tr>
    <td>Graph 1</td>
    <td><INPUT TYPE="radio" NAME="graph" VALUE="radio1"></td>
    </tr>

    </table>
    <form action="${pageContext.request.contextPath}/myservlet" method="post">
    <input type="submit" value="Submit" name="submit" />
    </form>
    </div>
</body>

那里非常简单。

这是servlet：

@WebServlet("/myservlet")
public class MyServlet extends HttpServlet {

    @Override
        protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
            UnixPrompt unixprompt = new UnixPrompt();
            unixprompt.connect();
        }       
    }

这是连接到ssh并执行命令的代码：

import com.jcraft.jsch.*;

import java.io.*;

public class UnixPrompt{
  public static void connect(){
    try{
      JSch jsch=new JSch();  

      String host=null;

      String user="******";
      host="*******";
      String config =
                "Port 22\n"+
                "\n"+
                "Host foo\n"+
                "  User "+user+"\n"+
                "  Hostname "+host+"\n"+
                "Host *\n"+
                "  ConnectTime 30000\n"+
                "  PreferredAuthentications keyboard-interactive,password,publickey\n"+
                "  #ForwardAgent yes\n"+
                "  #StrictHostKeyChecking no\n"+
                "  #IdentityFile ~/.ssh/id_rsa\n"+
                "  #UserKnownHostsFile ~/.ssh/known_hosts";



              ConfigRepository configRepository =
                com.jcraft.jsch.OpenSSHConfig.parse(config);


              jsch.setConfigRepository(configRepository);
              Session session=jsch.getSession("foo");


      String passwd ="*****";
      session.setPassword(passwd);
      UserInfo ui = new MyUserInfo(){

          public boolean promptYesNo(String message){

            int foo = 0;
            return foo==0;
          }
      };
      session.setUserInfo(ui);
      session.connect();

      String command="pwd";

      Channel channel=session.openChannel("exec");
      ((ChannelExec)channel).setCommand(command);


      channel.setInputStream(null);


      ((ChannelExec)channel).setErrStream(System.err);

      InputStream in=channel.getInputStream();

      channel.connect();

      byte[] tmp=new byte[1024];
      while(true){
        while(in.available()>0){
          int i=in.read(tmp, 0, 1024);
          if(i<0)break;
          System.out.print(new String(tmp, 0, i));
        }
        if(channel.isClosed()){
          if(in.available()>0) continue; 
          System.out.println("exit-status: "+channel.getExitStatus());
          break;
        }
        try{Thread.sleep(1000);}catch(Exception ee){}
      }

      channel.disconnect();
      session.disconnect();
    }
    catch(Exception e){
      System.out.println(e);
    }


  }
  public static void main(String arg[]){
    connect();
  }

  public static abstract class MyUserInfo
    implements UserInfo, UIKeyboardInteractive{
public String getPassword(){ return null; }
public boolean promptYesNo(String str){ return false; }
public String getPassphrase(){ return null; }
public boolean promptPassphrase(String message){ return false; }
public boolean promptPassword(String message){ return false; }
public void showMessage(String message){ }
public String[] promptKeyboardInteractive(String destination,
                        String name,
                        String instruction,
                        String[] prompt,
                        boolean[] echo){
return null;
}
}
}

我可以通过独立的UnixPrompt类连接到SSH并执行命令，但是无法通过jsp执行此操作。

这是我得到的错误：

SEVERE：servlet [unix.MyServlet]的Servlet.service（）与上下文路径[/ Scratchpad]抛出异常[Servlet执行扔了一个异常]与根本原因java.lang.ClassNotFoundException： com.jcraft.jsch.ConfigRepository at org.apache.catalina.loader.WebappClassLoader.loadClass（WebappClassLoader.java:1858）在 org.apache.catalina.loader.WebappClassLoader.loadClass（WebappClassLoader.java:1709）在unix.MyServlet.doPost（MyServlet.java:17）at javax.servlet.http.HttpServlet.service（HttpServlet.java:650）at at javax.servlet.http.HttpServlet.service（HttpServlet.java:731）at at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter（ApplicationFilterChain.java:303）在 org.apache.catalina.core.ApplicationFilterChain.doFilter（ApplicationFilterChain.java:208）在 org.apache.tomcat.websocket.server.WsFilter.doFilter（WsFilter.java:52）在 org.apache.catalina.core.ApplicationFilterChain.internalDoFilter（ApplicationFilterChain.java:241）在 org.apache.catalina.core.ApplicationFilterChain.doFilter（ApplicationFilterChain.java:208）在 org.apache.catalina.core.StandardWrapperValve.invoke（StandardWrapperValve.java:220）在 org.apache.catalina.core.StandardContextValve.invoke（StandardContextValve.java:122）在 org.apache.catalina.authenticator.AuthenticatorBase.invoke（AuthenticatorBase.java:505）在 org.apache.catalina.core.StandardHostValve.invoke（StandardHostValve.java:170）在 org.apache.catalina.valves.ErrorReportValve.invoke（ErrorReportValve.java:103）在 org.apache.catalina.valves.AccessLogValve.invoke（AccessLogValve.java:956）在 org.apache.catalina.core.StandardEngineValve.invoke（StandardEngineValve.java:116）在 org.apache.catalina.connector.CoyoteAdapter.service（CoyoteAdapter.java:423）在 org.apache.coyote.http11.AbstractHttp11Processor.process（AbstractHttp11Processor.java:1079）在 org.apache.coyote.AbstractProtocol $ AbstractConnectionHandler.process（AbstractProtocol.java:625）在 org.apache.tomcat.util.net.JIoEndpoint $ SocketProcessor.run（JIoEndpoint.java:318）在 java.util.concurrent.ThreadPoolExecutor.runWorker（ThreadPoolExecutor.java:1145）在 java.util.concurrent.ThreadPoolExecutor中的$ Worker.run（ThreadPoolExecutor.java:615）在 org.apache.tomcat.util.threads.TaskThread $ WrappingRunnable.run（TaskThread.java:61）在java.lang.Thread.run（Thread.java:722）

错误引用的类存在于版本0.1.54的较新的JSch jar中，我已将其包含在构建路径中，所以我不确定问题是什么。

任何帮助将不胜感激

从jsp

0 个答案: