我是一名R程序员并且想到javascript中的数组类似于R中的列表。在R中,当我想访问列表的元素时,我会使用lapply()
和do.call
来应用函数到内部元素,然后将结果放入新的数据结构中。我在javascript中读到了map
函数,但在我的情况下似乎无法解决它:
data = {"type": "FeatureCollection",
"crs": { "type": "name", "properties": { "name": "CRS" } },
"features": [
{ "type": "Feature",
"id": 6,
"properties": {"species": "giraffe",
"result": 0,
"popup_text": "Some text" },
"geometry": { "type": "Point", "coordinates": [ 1, 5] } },
{ "type": "Feature",
"id": 7,
"properties": { "species": "pig",
"result": 0,
"popup_text": "Some text" },
"geometry": { "type": "Point", "coordinates": [ 2,3 ] } },
{ "type": "Feature",
"id": 8,
"properties": { "species": "goat",
"result": 0,
"popup_text": "Some Text" },
"geometry": { "type": "Point", "coordinates": [ 1,6 ] } },
{ "type": "Feature",
"id": 16,
"properties": { "species": "giraffe",
"result": 0,
"popup_text": "Some Text" },
"geometry": { "type": "Point", "coordinates": [ 3,4 ] } },
{ "type": "Feature",
"id": 18,
"properties": { "species": "pig",
"result": 0,
"popup_text": "Some Text" },
"geometry": { "type": "Point", "coordinates": [ 2,7 ] } }
]
}
因此,data.features
是一个包含5个元素的数组,每个元素包含4个数组:type
,id
,properties
,geometry
。我想生成一个只有properties.result
值的新数组。它会有这样的结构:
newdata = [0, 0, 0, 0, 0]
到目前为止,我尝试了以下内容,但它并没有产生我想要的结果:
var result = data.features.map(function(i) {
return{
result: i.properties.result
};
});
console.log(result)
我有什么想法可以做到这一点?最后,我的目的是确定any
result == 1
答案 0 :(得分:3)
要获得您想要的输出
var result = data.features.map(function(i) {
return i.properties.result;
});
这将产生一个[0,0,0,0,0]
数组。
要确定其中任何一个是否为1,您可以使用Array.some
var areAny1 = result.some(function(x) { return x == 1; });
下面的实例
var data = {"type": "FeatureCollection",
"crs": { "type": "name", "properties": { "name": "CRS" } },
"features": [
{ "type": "Feature",
"id": 6,
"properties": {"species": "giraffe",
"result": 0,
"popup_text": "Some text" },
"geometry": { "type": "Point", "coordinates": [ 1, 5] } },
{ "type": "Feature",
"id": 7,
"properties": { "species": "pig",
"result": 0,
"popup_text": "Some text" },
"geometry": { "type": "Point", "coordinates": [ 2,3 ] } },
{ "type": "Feature",
"id": 8,
"properties": { "species": "goat",
"result": 0,
"popup_text": "Some Text" },
"geometry": { "type": "Point", "coordinates": [ 1,6 ] } },
{ "type": "Feature",
"id": 16,
"properties": { "species": "giraffe",
"result": 0,
"popup_text": "Some Text" },
"geometry": { "type": "Point", "coordinates": [ 3,4 ] } },
{ "type": "Feature",
"id": 18,
"properties": { "species": "pig",
"result": 0,
"popup_text": "Some Text" },
"geometry": { "type": "Point", "coordinates": [ 2,7 ] } }
]
};
var result = data.features.map(function(x){
return x.properties.result;
});
console.log(result);
var areAny1 = result.some(function(x) { return x === 1 });
console.log(areAny1);

答案 1 :(得分:0)
我想生成一个新的数组 properties.result值。
你几乎走在正确的道路上
var result = data.features.map(function(i) {
return i.properties.result;
});
console.log(result)
最后我的目的是确定是否有任何结果== 1
您可以使用filter
var hasAny1 = data.features.filter(function(i) {
return i.properties.result == 1;
}).length > 0;
console.log(hasAny1);
或使用some
var hasAny1 = data.features.some(function(i) {
return i.properties.result == 1;
});
console.log(hasAny1);
答案 2 :(得分:0)
您应该只返回您想要成为新数组元素的值:
data.features.map(function (x) {
return x.properties.result;
});