Question

我目前正在处理包含以下代码的SQL Server JOB文件

@active_end_date = 99991231, 
@active_start_time = 0, 
@active_end_time = 235959, 
@schedule_uid = N'59cbfb7d-67c7-495c-810d-0ca7a6357f9c'

IF (@@ERROR <> 0 OR @ReturnCode <> 0) GOTO QuitWithRollback

我正在使用PowerShell通过以下代码删除@schedule_uid：

$orgineel_localfolder = "C:\Users\Desktop\Jobs_from_Server\aangepast"

$stringtorremove = '@schedule_uid='

$files = Get-ChildItem $orgineel_localfolder *.sql 

ForEach ($file in $files)
{
    $linenumber = Select-String $file -pattern $stringtorremove     
    $removecomma = $linenumber -replace",",""

    $fileName = "C:\Users\EX27740\Desktop\Jobs_from_Server\Orgineel\" + $file.Name.replace("_Orgineel","_nieuwe") # Vervangt alle Orgineel maar niet erg script blijft goed

   (Get-Content $file.fullname) -notmatch $stringtorremove | Out-File $fileName
    }

我的问题是上一行@active_end_time = 235959,。因为这一行中的数据并不总是@active_end_time，所以我想通过检索我将删除的行的行号来获得该行的行号。

我该怎么做？

Answer 1

我想通过检索将删除的行的行号-1来获取此行的行号。我怎么能这样做？

要查找该行号，您可以使用LineNumber并减去1：

$number = (Select-String $file -pattern $stringtorremove |  Select-Object -ExpandProperty LineNumber) - 1

Answer 2

如果其他人有类似的问题，我想我会发布我的解决方案：

$orgineel_localfolder = "C:\Users\Desktop\Jobs_from_Server\aangepast"

$stringtorremove = '@schedule_uid='

ForEach ($file in $files){
#gets the line number of the value 
$huidigeregel = Select-String $file -pattern $stringtorremove | Select-Object -ExpandProperty 'LineNumber'

if ([string]::IsNullOrWhitespace($huidigeregel )){
'Deze job heeft geen @schedule_uid= '
} else { 
#get the right line by subtracting the current line with -2
$goederegel = $huidigeregel -2
$valuewithcomma = get-content $file.fullname  | select -Index $goederegel
$valuewithoutcomma = $valuewithcomma -replace",",""
$orginalithcomma= Get-Content $file.fullname
}

$fileName = "C:\Users\Desktop\Jobs_from_Server\aangepast\" + $file.Name.replace("_Orgineel","_nieuwe")   

if ([string]::IsNullOrWhitespace($huidigeregel)){
(Get-Content $file.fullname) -notmatch $stringtorremove | Out-File $fileName
} else {
(Get-Content $file.fullname) -replace $valuewithcomma, $valuewithoutcomma -notmatch $stringtorremove | Out-File $fileName }  
}

如何删除以前字符串的一部分

2 个答案: