我有一个数据框,我需要根据两个值进行清算:#34;准相同"在行中。我只需删除不同但不相同的观察结果。我尝试使用agrep
执行此操作,但此功能也会删除相同的观察结果。
Id<-c("RoLu1976","Rolu1976","RoLu1976","AlBl1989","ThSa1996")
Art<-c("Econometric Policy Evaluation: A Critique","Econometric Policy Evaluations A Critique","Econometric Policy Evaluation: A Critique", "Rules after discretion", "Expectations and the Nonneutrality of Lucas")
Id.1<-c("FiKy1989","FiKy1989","BeBe1983","JoSt1989","JoSt1990")
Art.1<-c("Notes on the Lucas Critique","Notes on the Lucas Critique","The Inconsistency of Optimal Plans","The Inconsistency","Notes on the Lucas")
N<-data.frame(Id,Art,Id.1,Art.1)
以上dataframe
中的准相同值位于第一次观察的Art
列中,仅对于s
和:
而言不同。
在上述情况下,最终数据框应该是(请注意,相同的值不会被删除):
Id Art Id.1 Art.1
RoLu1976 Econometric Policy Evaluation: A Critique FiKy1989 Notes on the Lucas Critique
RoLu1976 Econometric Policy Evaluation: A Critique BeBe1983 The Inconsistency of Optimal Plans
AlBl1989 Rules after discretion JoSt1989 The Inconsistency
ThSa1996 Expectations and the Nonneutrality of Lucas JoSt1990 Notes on the Lucas
我所做的是this:
yy = NULL
for(i in 1:length(N$Art)){
temp = agrep(N[i,"Art"],N$Art,value=T)
y = ifelse(any(N[i,"Art"]==temp),temp[1],N[i,"Art"])
yy = c(yy,y)
}
N$Art = yy
N.2 = N[!duplicated(N$Art), ]
但它删除了两个值:相同和准相同。
我该怎么做?
答案 0 :(得分:3)
您可以存储原始Art列中相同内容的索引,并将其与重复数据删除后的结果结合使用,例如
originallyDuplicated <- duplicated(N$Art)
# then run your snippet to generate `yy`
所以你想摆脱那些重复的东西现在,而不是最初的。
N[!(duplicated(yy) & !originallyDuplicated),]
虽然对我来说,似乎不是纯粹基于Art
列的排除标准,但如果行中的每列重复排除行,则更有意义。表中的其他地方或几乎重复。 (例如,比较Art.1,Id.1,ID等列?)