Question

我需要一些帮助，我尝试在

中点击链接

echo "<p><a href="https://www.auno.org/ao/db.php?id=".$results['lowid']."<h3>".$results['name']."</h3>".$results['lowql']."<h3>".$results['profession']."

“; 但在我尝试添加超链接之前，我没有运气，但我不确定我做错了什么。

这是原始代码

echo "<p><h3>".$results['name']."</h3>".$results['lowql']."<h3>".$results['profession']."</p>";

该代码就像魅力一样，但我想让所有显示的项目都可以点击。但是当我编辑代码时，它完全破坏了。

   <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
   <html xmlns="http://www.w3.org/1999/xhtml">
 <head>
 <title>Search</title>
 <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
 <link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
<div class="results">

这里是php代码

<?php
$query = $_GET['query'];
// gets value sent over search form

$min_length = 0;
// you can set minimum length of the query if you want

if(strlen($query) >= $min_length){ // if query length is more or equal minimum length then

    $query = htmlspecialchars($query);
    // changes characters used in html to their equivalents, for example: < to &gt;

    $query = mysql_real_escape_string($query);
    // makes sure nobody uses SQL injection

    $raw_results = mysql_query("SELECT name FROM nanos
        WHERE (`name` LIKE '%".$query."%') OR (`lowql` LIKE '%".$query."%') OR (`profession` LIKE '%".$query."%') OR (`lowid` LIKE '%".$query."%')") or die(mysql_error());

    // * means that it selects all fields, you can also write: `id`, `title`, `text`
    // articles is the name of our table

    // '%$query%' is what we're looking for, % means anything, for example if $query is Hello
    // it will match "hello", "Hello man", "gogohello", if you want exact match use `title`='$query'
    // or if you want to match just full word so "gogohello" is out use '% $query %' ...OR ... '$query %' ... OR ... '% $query'

    if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following

        while($results = mysql_fetch_array($raw_results)){
        // $results = mysql_fetch_array($raw_results) puts data from database into array, while it's valid it does the loop

            echo "<p><a href="https://www.auno.org/ao/db.php?id=".$results['lowid']."<h3>".$results['name']."</h3>".$results['lowql']."<h3>".$results['profession']."</p>";
            // posts results gotten from database(title and text) you can also show id ($results['id'])
        }
    }
    else{ // if there is no matching rows do following
        echo "No results";
    }

}
else{ // if query length is less than minimum
    echo "Minimum length is ".$min_length;
}
?>

Answer 1

如果a的目的是使用url variables/parameters重定向页面，那么这将完成工作：

<?php 

  $lowid = 1;
  $name = 2;
  $lowql = 3;
  $prof = 4;

  echo "<a href=https://www.auno.org/ao/db.php?id=".$lowid."&name=".$name."&lowql=".$lowql."&prof=".$prof.">Click Me</a>";

?>

您只需使用$_GET['variable_name']中的search.php获取值。

我认为h3中不需要url。

在php中为mysql制作可点击链接

1 个答案: