我需要访问topBox的孙子,并确定它们是否是按钮。
下面的这个功能(谢谢Flextras.com)抓住了topBox的直接孩子,这些孩子就是HBox。我如何进入topBox的孙子级别?或者唯一的方法是在每个HBox上运行此功能吗?
for (var i : int =0; i<topBox.numChildren; i++){
var child : DisplayObject = topBox.getChildAt(i);
var myButton:UIComponent = child as UIComponent;
blah blah
}
<mx:VBox id="topBox">
<mx:HBox id="Hbox1">
<mx:Button id="button1"
label="button1"
click="myClickHandler"/>
<mx:Button id="button2"
label="button2"
click="myClickHandler"/>
</mx:HBox>
<mx:HBox id="Hbox2">
<mx:Button id="button3"
label="button3"
click="myClickHandler"/>
<mx:Button id="button4"
label="button4"
click="myClickHandler"/>
</mx:HBox>
<mx:VBox>
答案 0 :(得分:2)
//declare child access function
private function processChildren(target:DisplayObjectContainer, handler:Function):void
{
for (var i:int = target.numChildren - 1; i >= 0; i--)
{
handler(target.getChildAt(i));
}
}
//call it with handler as anonymous function (may be plain one as well)
processChildren(topBox, function(target:DisplayObjectContainer):void
{
processChildren(target, function(target:DisplayObjectContainer):void
{
//this will be called on grandchildren
if (target is Button)
{
//do something
}
});
});
为了让它看起来不那么令人生畏,可以用普通函数替换匿名函数,但这个想法应该是明确的。