Question

我觉得这应该很简单，但我没有得到我想要的结果。我有一个电子邮件注册表单，显示在我的所有网站上。如果他们碰巧使用商店代码ama_br访问我的网站，则电子邮件注册会消失。这很好，这很有效。我的elseif语句与所有商店视图中显示的语句不同，我希望此新表单仅在其存储代码ama_ca时显示。它对我不起作用，我的代码也没有任何问题。请帮忙。谢谢。

            <?php if (Mage::app()->getStore()->getCode() != "ama_br"):?>
                <ul>
                    <li><?php echo $this->__('Email Sign Up')?></li>
                    <li>
                        <form action="<?php echo $this->getUrl('email_preferences')?>" method="get" id="newsletter-validate-detail">
                            <input name="email" type="text" id="newsletter" placeholder="<?php echo $this->__('Enter Email address')?>" title="<?php echo $this->__('Enter Email address')?>' class="required-entry validate-email">
                            <button class="submit">+</button>
                            <input type="hidden" name="source" value="nt">
                        </form>
                    </li>
                    <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo')?></li>
                </ul>

            <?php elseif (Mage::app()->getStore()->getCode() == "ama_ca"):?>
                <ul>
                    <li><?php echo $this->__('Email Sign Up')?></li>
                    <li>
                <form method="post" action="http://enews.******.com/q/9MNK4U4iV9Mutb9YzTxF2zRWDIPgKoX0F0" accept-charset="UTF-8">
                        <input type="hidden" name="crvs" value="6hZNXcISD79ac2Empmsr2az_B3Qc5osTNmkOdNHleqhPIYmsxEOe6PbgaUo-3WBn_Vbgorrbk4qjekx7w4tljA">
                        <input type="hidden" name="CheckBox.Source.ca_footer" value="on">
                        <input name="email" type="text" id="newsletter" placeholder="Enter Email address" title="Enter Email address' class=" required-entry="">
                        <input type="hidden" id="submit" value="Sign Up">
                        </form>
                    </li>
                    <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo')?></li>
                </ul>
            <?php endif;?>

Answer 1

<强>描述你已经完成了所有的事情，但你只是错过了你的if语句中的诀窍，如果你的代码不等于 ama_br 那就是它可以等于 ama_ca 所以它会在 ama_ca 的if语句中以及 ama_br 中的任何其他字符串中显示该表单，因此您尝试在代码上显示的表单等于 ama_ca 未显示。尝试以下方法之一，它将解决您的查询。

<强>代码

        <?php if (Mage::app()->getStore()->getCode() == "ama_ca"): ?>
          <ul>
            <li><?php echo $this->__('Email Sign Up') ?></li>
            <li>
            <form method="post" action="http://enews.******.com/q/9MNK4U4iV9Mutb9YzTxF2zRWDIPgKoX0F0" accept-charset="UTF-8">
            <input type="hidden" name="crvs" value="6hZNXcISD79ac2Empmsr2az_B3Qc5osTNmkOdNHleqhPIYmsxEOe6PbgaUo-3WBn_Vbgorrbk4qjekx7w4tljA">
            <input type="hidden" name="CheckBox.Source.ca_footer" value="on">
            <input name="email" type="text" id="newsletter" placeholder="Enter Email address" title="Enter Email address' class=" required-entry="">
            <input type="hidden" id="submit" value="Sign Up">
            </form>
            </li>
           <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo') ?></li>
         </ul>

        <?php elseif (Mage::app()->getStore()->getCode() != "ama_br"): ?>
          <ul>
            <li><?php echo $this->__('Email Sign Up') ?></li>
            <li>
              <form action="<?php echo $this->getUrl('email_preferences') ?>" method="get" id="newsletter-validate-detail">
              <input name="email" type="text" id="newsletter" placeholder="<?php echo $this->__('Enter Email address') ?>" title="<?php echo $this->__('Enter Email address') ?>' class="required-entry validate-email">
                   <button class="submit">+</button>
              <input type="hidden" name="source" value="nt">
              </form>
              </li>
              <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo') ?></li>
             </ul>
        <?php endif; ?>

或

<?php if (Mage::app()->getStore()->getCode() != "ama_br" && Mage::app()- >getStore()->getCode() != "ama_ca"): ?> <ul> <li><?php echo $this->__('Email Sign Up') ?></li> <li> <form action="<?php echo $this->getUrl('email_preferences') ?>" method="get" id="newsletter-validate-detail"> <input name="email" type="text" id="newsletter" placeholder="<?php echo $this->__('Enter Email address') ?>" title="<?php echo $this->__('Enter Email address') ?>' class="required-entry validate-email"> <button class="submit">+</button> <input type="hidden" name="source" value="nt"> </form> </li> <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo') ?></li> </ul> <?php elseif (Mage::app()->getStore()->getCode() == "ama_ca"): ?> <ul> <li><?php echo $this->__('Email Sign Up') ?></li> <li> <form method="post" action="http://enews.******.com/q/9MNK4U4iV9Mutb9YzTxF2zRWDIPgKoX0F0" accept-charset="UTF-8"> <input type="hidden" name="crvs" value="6hZNXcISD79ac2Empmsr2az_B3Qc5osTNmkOdNHleqhPIYmsxEOe6PbgaUo-3WBn_Vbgorrbk4qjekx7w4tljA"> <input type="hidden" name="CheckBox.Source.ca_footer" value="on"> <input name="email" type="text" id="newsletter" placeholder="Enter Email address" title="Enter Email address' class=" required-entry=""> <input type="hidden" id="submit" value="Sign Up"> </form> </li> <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo') ?></li> </ul> <?php endif; ?>

在PHP中嵌入条件if语句的html

1 个答案: