我的JSON具有以下结构:
[
{
"ID": 1,
"Label": "Reg Scheme",
"Colours": [
{
"ID": 1,
"Value": "0x3333cc",
"Result": 1,
"Label": null
},
{
"ID": 2,
"Value": "0x666699",
"Result": 2,
"Label": null
},
{
"ID": 3,
"Value": "0x009966",
"Result": 3,
"Label": null
}
]
},
{
"ID": 2,
"Label": "Spesh Scheme",
"Colours": [
{
"ID": 11,
"Value": "0x59699c",
"Result": 1,
"Label": null
},
{
"ID": 12,
"Value": "0x0070ff",
"Result": 2,
"Label": null
},
{
"ID": 13,
"Value": "0x90865e",
"Result": 3,
"Label": null
}
]
},
我有一个实体数据集,我加入了所有相关信息,并尝试通过单个linq-to-sql EF查询生成具有该结构的JSON,以返回到webapi方法。
到目前为止,我的查询是:
return
DbContext.Schemes
.Join(
DbContext.SchemeColours,
s => s.SchemeID,
sc => sc.SchemeID,
(s, sc) => new
{
s.SchemeID,
s.Label,
sc.Colour,
sc.Result,
sc.ColourID
})
.Select(a =>
new Overlay.ReportColourScheme
{
ID = a.SchemeID,
Label = a.Label,
Colours = new List<Overlay.ReportColour>
{
new Overlay.ReportColour
{
ID = a.ColourID,
Value = a.Colour,
Result = a.Result
}
}
})
.ToArray();
几乎存在但不完全:
[
{
"ID": 1,
"Label": "Regular Scheme",
"Colours": [
{
"ID": 1,
"Value": "0x3333cc",
"Result": 1,
"Label": null
}
]
},
{
"ID": 1,
"Label": "Regular Scheme",
"Colours": [
{
"ID": 2,
"Value": "0x666699",
"Result": 2,
"Label": null
}
]
},
{
"ID": 1,
"Label": "Regular Scheme",
"Colours": [
{
"ID": 3,
"Value": "0x009966",
"Result": 3,
"Label": null
}
]
},
{
"ID": 2,
"Label": "Protanopia adjusted Scheme",
"Colours": [
{
"ID": 11,
"Value": "0x59699c",
"Result": 1,
"Label": null
}
]
},
{
"ID": 2,
"Label": "Protanopia adjusted Scheme",
"Colours": [
{
"ID": 12,
"Value": "0x0070ff",
"Result": 2,
"Label": null
}
]
},
{
"ID": 2,
"Label": "Protanopia adjusted Scheme",
"Colours": [
{
"ID": 13,
"Value": "0x90865e",
"Result": 3,
"Label": null
}
]
},
当然,它会为每个resultID创建一个新列表。顶级ID是一个SchemeID-我正在寻找的逻辑是:“使用特定的schemeID获取前3个结果,将它们添加到Colors中的列表中,然后转到下一个schemeID”< / p>
我相信这会产生与我开始发布的相同的JSON。
非常感谢任何帮助,谢谢。
答案 0 :(得分:2)
请尝试以下代码:
<search-results #parent>
<div>{{ parent.item.title }}</div>
<div>{{ parent.item.id }} </div>
</search-results>
答案 1 :(得分:1)
主要问题是您使用的是Join
实际需要Group Join
的地方:
return DbContext.Schemes
.GroupJoin(DbContext.SchemeColours,
s => s.SchemeID,
sc => sc.SchemeID,
(s, colours) => new Overlay.ReportColourScheme
{
ID = s.SchemeID,
Label = s.Label,
Colours = colours
.Select(sc => new Overlay.ReportColour
{
ID = sc.ColourID,
Value = sc.Colour,
Result = sc.Result,
})
.ToList()
})
.ToArray();
但是,既然您正在使用实体框架,那么如果您定义(如果您已经没有)并使用导航属性,那将会更好更好用:
class Scheme
{
// ...
public ICollection<SchemeColour> Colours { get; set; }
}
然后简单地
return DbContext.Schemes
.Select(s => new Overlay.ReportColourScheme
{
ID = s.SchemeID,
Label = s.Label,
Colours = s.Colours
.Select(sc => new Overlay.ReportColour
{
ID = sc.ColourID,
Value = sc.Colour,
Result = sc.Result,
})
.ToList()
})
.ToArray();