如果多个记录具有相同的长度，则选择单个记录

Question

我正在尝试解决this problem on HackerRank

我尝试了这个查询：

select city, length(city) from station 
where length(city) = (select max(length(city)) from station)
      or length(city) = (select min(length(city)) from station)
order by
length(city) ASC,city ASC;

运行上述查询后，我得到以下结果：

Amo 3 
Lee 3 
Roy 3 
Marine On Saint Croix 21

我的问题是：我只想选择Amo＆amp; Marine On Saint Croix。不是其他人。 怎么做到这一点？

先谢谢

Answer 1

您可以尝试选择限制为1的最小和最大长度城市并将其合并吗？

select city, length(city) from station 
where  length(city) = (select max(length(city)) from station)
Limit  1
UNION
select city, length(city) from station 
where  length(city) = (select min(length(city)) from station)
Limit  1

Answer 2

以下是正确的查询：

 (SELECT city, LENGTH(city) AS length FROM station
ORDER BY LENGTH(city), city
LIMIT 1) UNION 

(SELECT city, LENGTH(city) AS length FROM station
ORDER BY LENGTH(city) DESC, city
LIMIT 1)