我是JS的新手,组织数据的概念让我有所收获,尝试从特定的数组格式中获取数据(因为这是我必须使用的)并将其输出为另一种特定的JSON格式。
这是为了将数据传递给D3 sankey模块 https://github.com/d3/d3-plugins/blob/master/sankey/sankey.js
我无法弄清楚如何将节点的索引添加到链接中,而不是名称。
真的,我完全迷失了它! 我在这里做了一个小提琴: https://jsfiddle.net/adamdavi3s/kw3jtzx4/
以下是数据和所需输出的示例
var data= [
{"source":"Agricultural 'waste'","target":"Bio-conversion","value":"124.2729"},
{"source":"Bio-conversion","target":"Electricity grid","value":"0.597"},
{"source":"Bio-conversion","target":"Losses","value":"26.862"},
{"source":"Bio-conversion","target":"Liquid","value":"280.322"},
{"source":"Losses","target":"Liquid","value":"280.322"}
];
var output= {
"nodes":[
{"name":"Agricultural 'waste'"},
{"name":"Bio-conversion"},
{"name":"Electricity grid"},
{"name":"Losses"},
{"name":"Liquid"}
],
"links":[
{"source":0,"target":1,"value":124.729},
{"source":1,"target":2,"value":0.597},
{"source":1,"target":3,"value":26.862},
{"source":1,"target":4,"value":280.322},
{"source":3,"target":4,"value":280.322}
]
};
这是来自小提琴的代码
var data=[{"source":"Agricultural 'waste'","target":"Bio-conversion","value":"124.2729"},
{"source":"Bio-conversion","target":"Electricity grid","value":"0.597"},
{"source":"Bio-conversion","target":"Losses","value":"26.862"},
{"source":"Bio-conversion","target":"Liquid","value":"280.322"},
{"source":"Losses","target":"Liquid","value":"280.322"}
];
var sourceArray=[];
for (var i=0; i <data.length; i++ ) {
var node= {"name":data[i].source};
var found = jQuery.inArray(node, sourceArray);
if (found < 0) {
// Element was not found, add it.
sourceArray.push(node);
}
}
console.log(sourceArray);
答案 0 :(得分:5)
在javascript中:
[]注释用于描述数组,如:
var names=["John","Lisa"]
{}用于描述对象
var person = {"name" : "John", "age" : 23}
您可以在彼此内部使用
var people=[{"name" : "John", "age" : 23},{"name" : "Lisa", "age" : 44}]
试试这个:
var data=[{"source":"Agricultural 'waste'","target":"Bio-conversion","value":"124.2729"},
{"source":"Bio-conversion","target":"Electricity grid","value":"0.597"},
{"source":"Bio-conversion","target":"Losses","value":"26.862"},
{"source":"Bio-conversion","target":"Liquid","value":"280.322"},
{"source":"Losses","target":"Liquid","value":"280.322"}
];
var sourceArray=[];
var linkArray=[];
for (var i=0; i <data.length; i++ ) {
var node= {"name":data[i].source,};
var link= {
"source":i,
"target":data[i].target,
"value":data[i].value,
};
var found = jQuery.inArray(node, sourceArray);
if (found >= 0) {
// Element was found, remove it.
sourceArray.splice(found, 1);
linkArray.splice(found, 1);
} else {
// Element was not found, add it.
sourceArray.push(node);
linkArray.push(link);
}
}
finalArray={"nodes": sourceArray,"links": linkArray}
console.log(finalArray);
答案 1 :(得分:4)
Array.reduce()
非常适合此用例;)
看看。
var data=[{"source":"Agricultural 'waste'","target":"Bio-conversion","value":"124.2729"},
{"source":"Bio-conversion","target":"Electricity grid","value":"0.597"},
{"source":"Bio-conversion","target":"Losses","value":"26.862"},
{"source":"Bio-conversion","target":"Liquid","value":"280.322"},
{"source":"Losses","target":"Liquid","value":"280.322"}
];
var output = data.reduce(function(result, item){
for(key in search = ['source','target']) {
var value = item[search[key]];
if(! result.index.hasOwnProperty(value)){
result.index[value] = Object.keys(result.index).length;
result.nodes.push({name: value});
}
}
result.links.push({
source: result.index[item.source],
target: result.index[item.target],
value: Number(item.value)
});
return result;
}, {nodes: [], links: [], index: {}});
delete output.index;
console.log(output);