我正在尝试为我的UITableView页脚视图创建一个自定义视图,其中包含一个按钮。我可以在那里看到它,但当我触摸它时,没有任何反应......你能看出这里的错误:
- (void)viewDidLoad {
[super viewDidLoad];
if(self.tableView.tableFooterView == nil) {
//allocate the view if it doesn't exist yet
UIView *footerView = [[UIView alloc] init];
//create the button
UIButton *addNewBtn = [UIButton buttonWithType:UIButtonTypeCustom];
//the button should be as big as a table view cell
[addNewBtn setFrame:CGRectMake(0, 0, 320, [AddMerchantTVC cellHeight])];
//set title, font size and font color
[addNewBtn setTitle:@"Add New" forState:UIControlStateNormal];
[addNewBtn.titleLabel setFont:[UIFont boldSystemFontOfSize:20]];
[addNewBtn setTitleColor:[UIColor blackColor] forState:UIControlStateNormal];
[addNewBtn addTarget:self action:@selector(addNew:) forControlEvents:UIControlEventTouchUpInside];
UIImageView *cellGradient = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"cellGradient.png"]];
cellGradient.frame = CGRectMake(0, 54, 320, 16);
[footerView addSubview:cellGradient];
//add the button to the view
[footerView addSubview:addNewBtn];
footerView.userInteractionEnabled = YES;
self.tableView.tableFooterView = footerView;
self.tableView.tableFooterView.userInteractionEnabled = YES;
[footerView release];
[cellGradient release];
}
- (void)addNew:(id)sender {
// This is never called
NSLog(@"Touched.");
}
答案 0 :(得分:38)
您没有设置footerView的框架。将footerView的框架设置为至少与按钮一样高,否则触摸不会传递到按钮。
答案 1 :(得分:7)
- (CGFloat)tableView:(UITableView *)tableView heightForFooterInSection:(NSInteger)section {
return 50.0f;
}
把这个方法放在你的课堂上你的问题会解决.....
答案 2 :(得分:1)
它为我工作我只需添加
footerView.frame =CGRectMake(0, 300, 100, 100);
答案 3 :(得分:0)
在调用 viewForFooterInSection 之前,您需要设置tableView的 sectionFooterHeight 属性(无法在viewForFooterInSection方法中执行此操作)。
答案 4 :(得分:-8)
创建UIView的子类并包含以下方法:
- (UIView *)hitTest:(CGPoint)point withEvent:(UIEvent *)event {
return [super hitTest:point withEvent:event];
}
- (BOOL)pointInside:(CGPoint)point withEvent:(UIEvent *)event {
return [super pointInside:point withEvent:event];
}