Question

我正在使用PostgreSQL 8.2，我也是PostgreSQL的新手。

我必须在WHERE子句中添加一个条件，具体取决于字段的特定值（49）（ activity.type ）。这是我的查询：

SELECT activity.*
FROM activity 
LEFT JOIN event_types ON activity.customstatusid = event_types.id, getviewableemployees(3222, NULL) AS report 
WHERE 
( 
    CASE WHEN activity.type = 49 THEN 
    'activity.individualid IN(SELECT individualid from prospects where prospects.individualid = activity.individualid)' 
    ELSE 1 
    END 
)
AND activity.date BETWEEN '2016-10-01' AND '2016-10-06' 
AND activity.type IN (21, 22, 49, 50, 37, 199) 
AND (event_types.status = 1 or event_types.status IS NULL);

当我在PGSQL的命令行访问中运行上面的查询时，我得到以下错误：

ERROR:  invalid input syntax for integer: "activity.individualid IN(SELECT individualid from prospects where prospects.individualid = activity.individualid)"

我在这里缺少什么？

Answer 1

将where子句实现为：

WHERE (
    activity.type != 49 OR
    activity.individualid IN (
        SELECT individualid from prospects 
        WHERE prospects.individualid = activity.individualid)
)
AND activity.date BETWEEN '2016-10-01' AND '2016-10-06' 
AND activity.type IN (21, 22, 49, 50, 37, 199) 
AND (event_types.status = 1 or event_types.status IS NULL);

第一个条款只有在以下任何一个情况下才会成立：

activity.type != 49;或
activity.type == 49和activity.individualid。

PostgreSQL：使用CASE在where子句中添加条件

1 个答案: