Question

我使用react 15.3.1，使用react-router 2.4.1和react-router-redux 4.0.5：

当我通过以下方式捕获路由更改时：

this.props.router.setRouteLeaveHook(
    this.props.route,
    this.routerWillLeave
);

private routerWillLeave = () => {
    if (this.state.editing)
        return 'You may have unsaved changes. Are you sure you want to leave?'
};

...我确实调用了我的this.routerWillLeave方法，但浏览器中的URL仍然发生了变化，因此即使用户决定不离开页面而停留在页面上，URL现在也是错误的。想法？

Answer 1

export default class extends Component {
  static contextTypes = {
    router: React.PropTypes.object.isRequired
  }

  state = {
    editing: true
  }

  componentDidMount() {

    this.context.router.setRouteLeaveHook(this.props.route, () => {
       if (this.state.editing) {
          return false;
          // At here you can give a confirm dialog, return true when confirm true
       }else {
           return true;
       }
    })
  }
}

Answer 2

如果您的react-route＆gt; 2.4，您也可以使用withRouter来包装您的组件，这可能会更好！

import React, {Component} from 'react';
import {render} from 'react-dom';
import {withRouter} from 'react-router';

export default withRouter(class extends Component {
  state = {
    unsaved: true
  }
  componentDidMount() {
    this.props.router.setRouteLeaveHook(this.props.route, () => {
      if (this.state.unsaved) {
        return false;
          // At here you can give a confirm dialog, return true when confirm true
       }else {
          return true;
       }
    })
  }
  render() {
    return (
      <div>
        <h2>About</h2>
        {this.props.children || "This is outbox default!"}
      </div>
    )
  }
})

Answer 3

this.routerWillLeave = this.routerWillLeave.bind(this)

react-router setRouteLeaveHook仍在更新URL

3 个答案: