我想在我的一个测试类中注入Configuration实例,我使用ConfiguredApp扩展我的测试类并注入Configuration,它看起来像这样:
@DoNotDiscover()
class MyApiServiceSpec extends FreeSpec with ScalaFutures with ConfiguredApp {
implicit val formats = DefaultFormats
implicit val exec = global
lazy val configuration = app.injector.instanceOf[Configuration]
"Global test" - {
"testcase 1" in {
Server.withRouter() {
case GET(p"/get/data") => Action { request =>
Results.Ok()
}
} { implicit port =>
WsTestClient.withClient { implicit client =>
val service = new MyApiService {
override def config: Configuration = configuration
override val ws: WSClient = client
}
whenReady(service.getData()) { res =>
//i will test stuff here
}
}
}
}
}
}
(MyApiService is a trait)
在嵌套套件上调用run时遇到异常 - ConfiguredApp需要与key关联的Application值 " org.scalatestplus.play.app"在配置图中。你忘记了吗? 使用@DoNotDiscover注释嵌套套件? java.lang.IllegalArgumentException:ConfiguredApp需要一个Application 与键相关联的值" org.scalatestplus.play.app"在配置中 地图。您是否忘记使用@DoNotDiscover注释嵌套套件?
有人知道为什么会这样......?
谢谢!333333
答案 0 :(得分:1)
我的回答不是当前问题的答案,但我想提出一些建议。如果你想为控制器或某些服务编写单元测试,我建议使用PlaySpec。为了测试环境注入自定义配置:
class TdiFnolControllerSpec extends PlaySpec with OneAppPerSuite {
val myConfigFile = new File("app/test/conf/application_test.conf")
val parsedConfig = ConfigFactory.parseFile(myConfigFile)
val configuration = ConfigFactory.load(parsedConfig)
implicit override lazy val app: Application = new GuiceApplicationBuilder()
.overrides(bind[Configuration].toInstance(Configuration(configuration)))
.build()
"YourControlelr #index" should {
"should be open" in {
val result = route(app, FakeRequest(GET, controllers.routes.YourController.index().url)).get
status(result) mustBe OK
}
}
}
答案 1 :(得分:0)
您似乎试图单独运行此测试。但是使用ConfiguredApp
,您必须使用套件运行此测试,例如
class AcceptanceSpecSuite extends PlaySpec with GuiceOneAppPerSuite {
override def nestedSuites = Vector(new MyApiServiceSpec)
}
注射看起来不错。