我需要能够使用鼠标点击位置绘制多边形。 这是我目前的代码:
//the drawshape varible is called when a button is pressed to select use of this tool
if (DrawShape == 4)
{
Point[] pp = new Point[3];
pp[0] = new Point(e.Location.X, e.Location.Y);
pp[1] = new Point(e.Location.X, e.Location.Y);
pp[2] = new Point(e.Location.X, e.Location.Y);
Graphics G = this.CreateGraphics();
G.DrawPolygon(Pens.Black, pp);
}
由于
答案 0 :(得分:4)
这里有一些示例代码:
private List<Point> polygonPoints = new List<Point>();
private void TestForm_MouseClick(object sender, MouseEventArgs e)
{
switch(e.Button)
{
case MouseButtons.Left:
//draw line
polygonPoints.Add(new Point(e.X, e.Y));
if (polygonPoints.Count > 1)
{
//draw line
this.DrawLine(polygonPoints[polygonPoints.Count - 2], polygonPoints[polygonPoints.Count - 1]);
}
break;
case MouseButtons.Right:
//finish polygon
if (polygonPoints.Count > 2)
{
//draw last line
this.DrawLine(polygonPoints[polygonPoints.Count - 1], polygonPoints[0]);
polygonPoints.Clear();
}
break;
}
}
private void DrawLine(Point p1, Point p2)
{
Graphics G = this.CreateGraphics();
G.DrawLine(Pens.Black, p1, p2);
}
答案 1 :(得分:3)
首先,添加以下代码:
List<Point> points = new List<Point>();
在您正在绘制的对象上,捕获OnClick事件。其中一个参数应该具有点击的X和Y坐标。将它们添加到点数组中:
points.Add(new Point(xPos, yPos));
最后,在绘制线条的地方,使用以下代码:
if (DrawShape == 4)
{
Graphics G = this.CreateGraphics();
G.DrawPolygon(Pens.Black, points.ToArray());
}
修改强>
好的,所以上面的代码并不完全正确。首先,它最有可能是Click事件而不是OnClick事件。其次,要获得鼠标位置,需要使用points数组声明两个变量
int x = 0, y = 0;
然后有一个鼠标移动事件:
private void MouseMove(object sender, MouseEventArgs e)
{
x = e.X;
y = e.Y;
}
然后,在您的Click事件中:
private void Click(object sender, EventArgs e)
{
points.Add(new Point(x, y));
}