Question

我正在尝试在Jqgrid表中选择单选按钮。但我无法找到它的XPath。

 `table id="list" class="ui-jqgrid-btable" tabindex="0" role="grid" aria-
  multiselectable="false" aria-labelledby="gbox_list" style="width: 940px;
  display: table;" cellspacing="0" cellpadding="0" border="0"> 
  <tbody>
  <tr class="jqgfirstrow" role="row" style="height:auto">
  <td role="gridcell" style="height:0px;width:20px;"></td>
  <td role="gridcell" style="height:0px;width:150px;display:none;"></td>
  </tr>
  <tr id="1" class="ui-widget-content jqgrow ui-row-ltr ui-state-highlight 
  gridRowSelect" role="row" tabindex="0" style="color: rgb(255, 0, 0);" 
  aria-selected="true">
  <td role="gridcell" style="text-align:center;" title="" aria-
  describedby="list_myradio">
  <input id="gridRadio" class="gridRadio" name="radio_list" type="radio">
  </td>`

Answer 1

我建议通过其唯一ID（driver.findElement(By.id("gridRadio"))）来选择它。但是，如果您明确要使用XPath，请使用以下表达式之一：

//input[@id='gridRadio']

或

//table[@id='list']/tbody/tr[@id='1']/td/input[@type='radio']

如何使用selenium webdriver在JQGrid中选择单选按钮

1 个答案: