我正在创建一个Web应用程序,其中我有一个包含5个其他页面的母版页
welcome
user
employee
admin
company
每个页面都有一个gridview(i.e I have 5 gridviews
)gridview包含不同页面的不同数据
我使用它将gridview数据导出到excel
protected void imgexcel_Click(object sender, ImageClickEventArgs e)
{
Response.Clear();
Response.Buffer = true;
Response.AddHeader("content-disposition", "attachment;filename=GridViewExport.xls");
Response.Charset = "";
Response.ContentType = "application/vnd.ms-excel";
StringWriter sw = new StringWriter();
HtmlTextWriter hw = new HtmlTextWriter(sw);
GridView1.AllowPaging = false;
GridView1.HeaderRow.Style.Add("background-color", "#FFFFFF");
for (int i = 0; i < GridView1.Rows.Count; i++)
{
GridViewRow row = GridView1.Rows[i];
row.BackColor = System.Drawing.Color.White;
row.Attributes.Add("class", "textmode");
}
GridView1.RenderControl(hw);
string style = @"<style> .textmode { mso-number-format:\@; } </style>";
Response.Write(style);
Response.Output.Write(sw.ToString());
Response.Flush();
Response.End();
}
这是我正常的导出编码
但我想在我的母版页上添加按钮,并且数据的导出取决于用户使用的页面(如果用户在欢迎页面上,欢迎页面的数据必须在按钮点击时导出,如果他在用户页面上并单击在按钮上单击用户的数据必须导出等等)
答案 0 :(得分:0)
string s = this.Page.Request.FilePath; // "/Welcome.aspx"
您可以使用此代码将页面名称保存在字符串中,这样您就可以在switch-case结构中使用此字符串(在按钮OnClick
中)。
switch(string)
{
case:"welcome": //...
case:"user": //...
case:"employee": //...
}
希望它有所帮助。
答案 1 :(得分:0)
您可以使用FindControl
在每个页面上查找GridView。您只需确保它们都具有相同的ID。
protected void Button1_Click(object sender, EventArgs e)
{
//first find the ContentPlaceHolder control
ContentPlaceHolder contentPlaceHolder = FindControl("ContentPlaceHolder1") as ContentPlaceHolder;
//then find the GridView control inside the ContentPlaceHolder
GridView gridview = contentPlaceHolder.FindControl("GridView1") as GridView;
//or the same as above but in a single line of code
GridView gridview = FindControl("ContentPlaceHolder1").FindControl("GridView1") as GridView;
//do stuff with the GridView
gridview.Visible = false;
}