Question

Jquery on time show and hide check box text if checked show the text if unchecked remove the text.

我正在尝试在左侧显示所选复选框文本，并在未选中时隐藏它这是我的代码，我尝试过：

<div class="products-row">
    <?php $tq=$conn->query("select * from os_tiffen where tiffen_status=1 order by id_tiffen ASC");
        while ($tiffen = $tq->fetch_assoc()) {
        ?>  
        <div class="col-md-3"> 
            <div class="foodmenuform row text-center">
                <input type="checkbox" id="<?php echo $tiffen['tiffen_image'];?>" hidden>
                <label for="<?php echo $tiffen['tiffen_image'];?>"><img src="img/tiffen/<?php echo $tiffen['tiffen_image']; ?>" alt="" class="img img-responsive" /></label>
                <h3 id="tiffenname"><?php echo $tiffen['tiffen_name'];?></h3>
            </div>
        </div>
    <?php }  ?>
</div>

这是我的剧本：

$( document ).ready(function() {
var FoodMenu = $('input[type=checkbox]:checked').map(function(){
return $(this).next('h3').text();
}).get().join("<br>");
$("#selectedfood").html(FoodMenu);
});

这是我展示输出的地方：

<div class="related-row" id="FoodSelected">
    <h4 class="text-center">Food Selected</h4> 
    <ul class="nav nav-pills nav-justified">
        <li class="active"><a id="selectedfood"></a></li>
    </ul>    
</div>

Answer 1

$(document).ready(function(){

$("input:checkbox").click(function() {
        var output = "";
        $("input:checked").each(function() {
            output += $(this).next('span').text();
        }); 
        if (output != '')
         $(".dropdown").append('<li>'+output+'</li>');  
  }); 
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="dropdown-content">

  <ul class="dropdown"></ul>
<ul>
  <li><input type="checkbox"/><span>one</span></li>  
  <li><input type="checkbox"/><span>two</span></li> 
  <li><input type="checkbox"/><span>three</span></li> 
  <li><input type="checkbox"/><span>four</span></li> 
  <li><input type="checkbox"/><span>five</span></li> 
  <li><input type="checkbox"/><span>six</span></li> 
  <li><input type="checkbox"/><span>seven</span></li> 
  <li><input type="checkbox"/><span>eight</span></li> 
  <li><input type="checkbox"/><span>nine</span></li> 
</ul>
</div>

尝试一次

Answer 2

请仔细查看您的布局，标签里面没有名字。可能的解决方案是将菜肴名称包装在容器中：

    <div class="col-md-3"> 
        <div class="foodmenuform row">
            <input type="checkbox"  id="<?php echo $lunch['id_lunch'];?>" />
            <span class="foodmenuform-name"><?php echo $lunch['lunch_name'];?></span>
            <label for="<?php echo $lunch['id_lunch'];?>"><img src="img/lunch/<?php echo $lunch['lunch_image']; ?>"/></label>
        </div>
    </div>

然后使用此容器获取菜名：

$( document ).ready(function() {
    //console.log( "ready!" );
    var FoodMenu = $('input[type=checkbox]:checked').map(function(){
        return $(this).next('.foodmenuform-name').text();
    }).get().join("</li><li>");
    $("#selectedfood").html("<ul><li>" + FoodMenu + "</li></ul>");
});

如何使用Jquery显示和隐藏复选框文本

2 个答案: