Question

我想创建一个python脚本，它有一个计数器，用于替换CSV文件中特定单元格的当前值。

我的代码是：

with open(ctlLst[-1], 'rb') as csvfile:
    csvReader = csv.reader(csvfile)
    csvReader.next()
    for row in csvReader:
        if row[6]>counter:
        newCTLcount=int(row[6])-counter
        #need to replace cell row[6]

该文件如下所示：

 InterfaceCode  InterfaceSeqID  OperatorCode    CreationDateTime    MintransactionDateTime  MaxtransactionDateTime  NoOfRows    ControlFileName DataFileName
201 1170    30  20161005 04:30:27   20161004 06:55:56   20161005 03:08:37   8696    CTL_TripEventAndAlert_30_20161004.CSV   TripEventAndAlert_30_20161004.CSV

在这个例子中，我需要用新值（newCTLcount）替换8696（第2行单元格6）的值。

Answer 1

最有可能的做法是在阅读/解析时编写以节省内存

with open('out.csv', 'wb') as outfile:
  with open(ctlLst[-1], 'rb') as csvfile:
    csvReader = csv.reader(csvfile)
    csvWriter = csv.writer(outfile)
    csvReader.next()
    for row in csvReader:
      row[6] = int(row[6]) # assumed as int
       if row[6] > counter:
         row[6] -= counter
      outfile.writerow(row)

对于Python 2，请参阅https://docs.python.org/2/library/csv.html

Answer 2

得到它......

 rowData=[]
 with open(ctlLst[-1], 'rb') as csvfile:
 csvReader = csv.reader(csvfile)
     for row in csvReader:
        rowData.append(row)

 rowData[1][6]=int(rowData[1][6])-counter
 print ("new Row data count is " + str(rowData[1][6]))

谢谢

如何替换csv文件的特定单元格中的值？

2 个答案: