我需要使用data
属性使用多个过滤器。它是组合工作但不是单独工作。这是我的代码:
<ul>
<li>
<div class="sts">
<h1>filter 1</h1>
</h1>
<div class="checkbox">
<label>
<input data-id="1" class="st" type="checkbox" />
1
</label>
</div>
<div class="checkbox">
<label>
<input data-id="2" class="st" type="checkbox" />
2
</label>
</div>
<div class="checkbox">
<label>
<input data-id="3" class="st" type="checkbox" />
3
</label>
</div>
</div>
</li>
<li>
<h1>filter 2</h1>
<div class="ats">
<div class="checkbox">
<label>
<input data-id="foo" class="at" type="checkbox" />
foo
</label>
</div>
<div class="checkbox">
<label>
<input data-id="boo" class="at" type="checkbox" />
boo
</label>
</div>
<div class="checkbox">
<label>
<input data-id="bar" class="at" type="checkbox" />
bar
</label>
</div>
</div>
</li>
<li>
<h1>filter 3</h1>
<div class="dpts">
<div class="checkbox">
<label>
<input data-id="a" class="dpt" type="checkbox" />
a
</label>
</div>
<div class="checkbox">
<label>
<input data-id="b" class="dpt" type="checkbox" />
b
</label>
</div>
<div class="checkbox">
<label>
<input data-id="c" class="dpt" type="checkbox" />
c
</label>
</div>
<div class="checkbox">
<label>
<input data-id="d" class="dpt" type="checkbox" />
d
</label>
</div>
</div>
</li>
</ul>
<ul class="list">
<li data-a="foo" data-st="1" data-dpt="a">asdw</li>
<li data-a="boo" data-st="2" data-dpt="c">qwedf</li>
<li data-a="boo" data-st="1" data-dpt="a">qwedf</li>
<li data-a="bar" data-st="3" data-dpt="b">tazxsw</li>
<li data-a="bar" data-st="1" data-dpt="b">zxcvb</li>
<li data-a="foo" data-st="1" data-dpt="b">poiuy</li>
<li data-a="boo" data-st="2" data-dpt="d">lkjhg</li>
<li data-a="boo" data-st="3" data-dpt="d">lkjhg</li>
</ul>
$(function() {
$('.at, .dpt,.st').on('click', function() {
var checkedat = $('.at:checked');
var checkeddept = $('.dpt:checked');
var checkedst = $('.st:checked');
if (checkedat.length || checkeddept.length || checkedst.length) {
if (checkeddept.length === 0) {
$('.list > li').hide();
$.each(checkedat, function() {
var prdId = $(this).attr('data-id');
$.each(checkedst, function() {
var brandId = $(this).attr('data-id');
$('.list > li[data-a="' + prdId + '"][data-st="' + brandId + '"]').show();
});
});
} else if (checkedat.length === 0) {
$('.list > li').hide();
$.each(checkedst, function() {
var brandId = $(this).attr('data-id');
$.each(checkeddept, function() {
var DeptId = $(this).attr('data-id');
$('.list > li[data-st="' + brandId + '"][data-dpt="' + DeptId + '"]').show();
});
});
} else if (checkedat.length === 0) {
$('.list > li').hide();
$.each(checkeddept, function() {
var DeptId = $(this).attr('data-id');
$.each(checkedst, function() {
var brandId = $(this).attr('data-id');
$('.list > li[data-dpt="' + DeptId + '"][data-st="' + brandId + '"]').show();
});
});
} else {
$('.list > li').hide();
$.each(checkedat, function() {
var prdId = $(this).attr('data-id');
$.each(checkedst, function() {
var brandId = $(this).attr('data-id');
$.each(checkeddept, function() {
var DeptId = $(this).attr('data-id');
$('.list > li[data-a="' + prdId + '"][data-dpt="' + DeptId + '"][data-st="' + brandId + '"]').show();
});
});
});
}
} else {
$('.list > li').show();
}
});
});
如果我检查过滤器1和过滤器中的任何选项过滤器2&amp;过滤3它的工作,但是当我点击过滤器1或过滤器2中的任何选项时它不起作用
答案 0 :(得分:1)
你的逻辑很多比它需要的更复杂。你应该考虑使用DRY原则,因为你可以更简单。
首先,在所有复选框上放置一个公共类(我在我的示例中使用了.stat
)。然后使用data属性表示stat的类型。在那里,您可以循环浏览每个已检查的统计信息,并使用li
隐藏/显示相关的filter()
,以便根据data-stat
和data-id
进行匹配。像这样:
$('.stat').on('click', function() {
var $stats = $('.stat:checked');
var $items = $('.list li');
$items.show();
if ($stats.length == 0)
return;
$stats.each(function() {
var $stat = $(this);
$items.filter(function() {
return $(this).data($stat.data('type')) != $stat.data('id');
}).hide();
})
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul>
<li>
<div class="sts">
<h1>filter 1</h1>
<div class="checkbox">
<label>
<input data-id="1" data-type="st" class="stat st" type="checkbox" />1
</label>
</div>
<div class="checkbox">
<label>
<input data-id="2" data-type="st" class="stat st" type="checkbox" />2
</label>
</div>
<div class="checkbox">
<label>
<input data-id="3" data-type="st" class="stat st" type="checkbox" />3
</label>
</div>
</div>
</li>
<li>
<h1>filter 2</h1>
<div class="ats">
<div class="checkbox">
<label>
<input data-id="foo" data-type="at" class="stat at" type="checkbox" />foo
</label>
</div>
<div class="checkbox">
<label>
<input data-id="boo" data-type="at" class="stat at" type="checkbox" />boo
</label>
</div>
<div class="checkbox">
<label>
<input data-id="bar" data-type="at" class="stat at" type="checkbox" />bar
</label>
</div>
</div>
</li>
<li>
<h1>filter 3</h1>
<div class="dpts">
<div class="checkbox">
<label>
<input data-id="a" data-type="dpt" class="stat dpt" type="checkbox" />a
</label>
</div>
<div class="checkbox">
<label>
<input data-id="b" data-type="dpt" class="stat dpt" type="checkbox" />b
</label>
</div>
<div class="checkbox">
<label>
<input data-id="c" data-type="dpt" class="stat dpt" type="checkbox" />c
</label>
</div>
<div class="checkbox">
<label>
<input data-id="d" data-type="dpt" class="stat dpt" type="checkbox" />d
</label>
</div>
</div>
</li>
</ul>
<ul class="list">
<li data-at="foo" data-st="1" data-dpt="a">asdw</li>
<li data-at="boo" data-st="2" data-dpt="c">qwedf</li>
<li data-at="boo" data-st="1" data-dpt="a">qwedf</li>
<li data-at="bar" data-st="3" data-dpt="b">tazxsw</li>
<li data-at="bar" data-st="1" data-dpt="b">zxcvb</li>
<li data-at="foo" data-st="1" data-dpt="b">poiuy</li>
<li data-at="boo" data-st="2" data-dpt="d">lkjhg</li>
<li data-at="boo" data-st="3" data-dpt="d">lkjhg</li>
</ul>
以上是对每个选择的选项执行'AND'逻辑。要将其更改为“或”,请使用以下内容:
$('.stat').on('click', function() {
var $stats = $('.stat:checked');
var $items = $('.list li');
if ($stats.length == 0) {
$items.show();
return;
}
$items.hide();
$stats.each(function() {
var $stat = $(this);
$items.filter(function() {
return $(this).data($stat.data('type')) == $stat.data('id');
}).show();
})
});