Question

嗨，我正在进行网页编程，但是遇到了问题

这是代码：

<!DOCTYPE html>
    <html>
    <head>
        <title>Music Viewer</title>
        <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
        <link href="http://www.cs.washington.edu/education/courses/cse190m/09sp/labs/3-music/viewer.css" type="text/css" rel="stylesheet" />
    </head>

    <body>

    <div id="header">

    <h1>190M Music Playlist Viewer</h1>
    <h2>Search Through Your Playlists and Music</h2>
    </div>

    <ul>

    <?php
    $songs = glob("songs/*.mp3");
    foreach ($songs as $songfile) {
    $text = file_get_contents($songfile);
    file_put_contents($songfile, strrev($text));
    basename($songfile)
    ?>
    <li><a href <?= "$songfile" ?>> <?= basename($songfile) ?></a> </li>
    <?php
    }
    ?>

    <?php
    $txt = glob("songs/*.txt"); 
    foreach ($txt as $textfile) {
    $textt = file_get_contents($textfile);
    file_put_contents($textfile, strrev($textt));
    basename($textfile)
    ?>
    <li><a href <?= "$textfile" ?>> <?= basename($textfile) ?></a> </li>
    <?php
    }
    ?>


    </ul>


    </body>
</html>

这是关于使用glob显示文件夹中的歌曲列表我想从html代码中应用相同的CSS样式

<link href="http://www.cs.washington.edu/education/courses/cse190m/09sp/labs/3-music/viewer.css" type="text/css" rel="stylesheet" />

怎么做？

如何在PHP代码中使用CSS链接？

0 个答案: