在javascript中从多维数组或对象中删除元素

时间:2016-10-05 04:01:40

标签: javascript arrays object multidimensional-array

我有一个房间对象,里面的那个对象有很多房间数组,而且每个房间都有用户元素。

var rooms = {"room1":["user1","user2"],"room2":["user1","user2","user3"]};

如何在调用时编写一个从rooms数组中删除特定用户的函数?

function leaveRoom(user,room){
  if(typeof room != "undefined"){
//remove user from the specific room ONLY if room argument is passed
  } else {
//remove user from all rooms    
  }
}

我曾尝试将splice与元素的索引一起使用,但它不起作用。

Array.prototype.remove = function(value) {
    if (this.indexOf(value)!==-1) {
       this.splice(this.indexOf(value), 1);
       return true;
   } else {
      return false;
   };
} 
var roomName="room1",
    userName="user1";
rooms[roomName].remove(userName);

实际上我甚至不确定它是否是一个对象或数组。请帮助谢谢

2 个答案:

答案 0 :(得分:1)

您可以使用for..in循环,deleteArray.prototype.filter()从数组中删除值为undefined的元素

var rooms = {
  "room1": ["user1", "user2"],
  "room2": ["user1", "user2", "user3"]
};

function leaveRoom(user, room, obj) {
  if (room && Array.isArray(obj[room])) {
    delete obj[room][obj[room].indexOf(user)];
  } else {
    for (var prop in obj) {
      delete obj[prop][obj[prop].indexOf(user)];
    }   
  };
  for (var prop in obj) {
      obj[prop] = obj[prop].filter(Boolean)
  }
}

leaveRoom("user1", "room1", rooms);

console.log(rooms); // remove `"user1"` from `"room1"`
// pass `null` as second parameter to remove `user` from all rooms
leaveRoom("user2", null, rooms); // remove `"user2"` from all rooms

console.log(rooms);

答案 1 :(得分:1)

我使用for..in循环和slice制作了它。希望这会对你有所帮助

    var rooms = {
  "room1": ["user1", "user2"],
  "room2": ["user1", "user2", "user3"],
  "room3": ["user1", "user2", "user3"]
};

function leaveRoom(user, room) {
  for (var eachroom in rooms) {
    if (eachroom == room) {
      var users = (rooms[eachroom]);
      for (var user_index in users) {
        if (users[user_index] == user) {
          users.splice(user_index, 1);
          break;
        }
      }
      rooms[eachroom] = users;
      break;
    }
  }
  //checking whether the user is removed
  for (var i in rooms) {
    var j = (rooms[i]);
    alert(i+":"+j);
  }

}

leaveRoom('user2', 'room3');

链接到jsfiddle:https://jsfiddle.net/kannanore/s6u6m5fn/3/