Question

我有一个包含StudentID，ClassID，ExamID，SubjectID和Scores字段的表我试图从每个学生的尝试科目中获得7个最高分的总和。下面的SQL语句给出了前七名学生所有科目的总分：

SELECT TOP 7 Sum(tblScores.Scores) AS Total, tblScores.AdmissionID
FROM tblScores
WHERE (((tblScores.ExamID)=[Forms]![frmReports]![lstC]) AND ((tblScores.ClassID)=[Forms]![frmReports]![lstB]))
GROUP BY tblScores.AdmissionID
ORDER BY Sum(tblScores.Scores) DESC;

从“frmReports”表单

中读取班级和考试标准

任何可以帮助我的人？

Answer 1

考虑相关子查询来计算得分的运行等级。然后，将此选择查询嵌套在 Score 聚合的派生表中，按每个学生的前7个分数（包括关系）进行筛选：

SELECT main.AdmissionID, Sum(main.Scores) As [Total]
FROM
  (SELECT tblScores.AdmissionID, tblScores.Scores,
         (SELECT Count(*) FROM tblScores sub
          WHERE sub.AdmissionID = tblScores.AdmissionID
          AND sub.Scores >= tblScores.Scores) As ScoreRank
   FROM tblScores
   WHERE (((tblScores.ExamID)=[Forms]![frmReports]![lstC])
     AND  ((tblScores.ClassID)=[Forms]![frmReports]![lstB]))
  ) As main
WHERE main.ScoreRank <= 7   
GROUP BY main.AdmissionID

Answer 2

试试这个：

SELECT TOP 7 Sum(tblScores.Scores) AS Total, tblScores.AdmissionID
FROM tblScores
HAVING (((tblScores.ExamID)=[Forms]![frmReports]![lstC]) AND ((tblScores.ClassID)=[Forms]![frmReports]![lstB]))
GROUP BY tblScores.AdmissionID
ORDER BY Sum(tblScores.Scores) DESC;

Answer 3

@ Parfait - 感谢您的指导。我实际上已经调整了你的解决方案以获得一个完美的答案：这是sql：

SELECT Dupe.AdmissionID，Dupe.Scores，Dupe.ScoreRank FROM（SELECT qryFilteredScores.AdmissionID，qryFilteredScores.Scores，（SELECT Count（*）FROM qryFilteredScores AS sub
WHERE sub.AdmissionID = qryFilteredScores.AdmissionID AND sub.Scores＆gt; qryFilteredScores.Scores）+ 1 AS ScoreRank FROM qryFilteredScores WHERE（（（qryFilteredScores.ExamID）= Forms！frmReports！lstC）And（（qryFilteredScores.ClassID）= Forms！frmReports ！lstB）））AS Dupe WHERE（（（Dupe.Scores）＆lt;＆gt; 0）AND（（Dupe.ScoreRank）＆lt; = 7））;

或者，您可以使用派生表或存储查询（将派生表保存为此查询中引用的单独对象）并避免内联子查询：

SELECT Dupe.AdmissionID, Total.TotalScore
FROM qryFilteredScores AS Dupe
INNER JOIN
     (SELECT sub.AdmissionID, Sum(sub.Scores) As TotalScore
      FROM qryFilteredScores sub
      WHERE ([AdmissionID]=Dupe.[AdmissionID] 
      AND ((sub.ClassID)=[Forms]![frmReports]![lstB]) 
      AND ((tblScores.ExamID)=[Forms]![frmReports]![lstC]))
      GROUP BY sub.AdmissionID) AS Total
ON Dupe.AdmissionID = Total.AdmissionID 
GROUP BY Dupe.AdmissionID, Total.TotalScore
ORDER BY Dupe.AdmissionID;

选择TOP谓词

3 个答案: