Question

我正在尝试使用日期键创建一个引用表，显示所有日期以及我的表中的引用。但是，这并不像我期望的那样有效。

DECLARE
  start_date DATE := TO_DATE('2009-01-01','YYYY-RR-DD');
  end_date DATE := TO_DATE('2021-01-01','YYYY-RR-DD');
BEGIN
  WHILE start_date < end_date LOOP
      SELECT 
            TO_CHAR(start_date, '-YYYYMMDD') AS DATE_KEY
          , TO_CHAR(start_date, 'YYYY-MM-DD') AS "ACTUAL_DATE"
          , EXTRACT(YEAR FROM start_date) AS "YEAR"
          , EXTRACT(MONTH FROM start_date) AS "MONTH"
          , TO_CHAR(start_date, 'MONTH') AS "MONTH_NAME"
          , TO_CHAR(start_date, 'WW') AS "WEEK_OF_YEAR"
          , EXTRACT(DAY FROM start_date) AS "DAY"
          , TO_CHAR(start_date, 'DDD') AS "DAY_OF_YEAR"
          , TO_CHAR(start_date, 'DAY') AS "WEEKDAY"
          , TO_CHAR(start_date, 'Q') AS "QTR_OF_YEAR"
          , TO_CHAR(start_date, 'MONTH DD, YYYY') AS FRIENDLY
      INTO V_DATE
      FROM dual;
      start_date := start_date+1;
  END LOOP;
END;

我收到此错误，但无论我尝试什么，我都会遇到错误。我已经尝试声明V_DATE，但这没有正常工作。

作为解决方法，我能够在Excel中创建所需的表，但它有一个小问题一周的一周。我可以在加载此数据后使用更新查询来解决此问题。拥有一个将填充的实际查询是理想的，因为这些数据可能会超出我列出的额外年份。

谢谢Allan

Answer 1

语法：

select . . .
into v_date
. . .

用于（在Oracle中）选择变量。

您似乎想在表中插入行：

insert into ??( . . . )
    <your select here>;

??是您的表名。 . . .是列的列表。

此外，您可以免除PL / SQL，并通过使用CTE生成所有日期（使用connect by或递归CTE）在单个查询中完成所有操作）。

Answer 2

您可以使用以下语句创建表：

  CREATE TABLE refdates AS 
  SELECT 
        TO_CHAR(start_date, '-YYYYMMDD') AS DATE_KEY
      , TO_CHAR(start_date, 'YYYY-MM-DD') AS "ACTUAL_DATE"
      , EXTRACT(YEAR FROM start_date) AS "YEAR"
      , EXTRACT(MONTH FROM start_date) AS "MONTH"
      , TO_CHAR(start_date, 'MONTH') AS "MONTH_NAME"
      , TO_CHAR(start_date, 'WW') AS "WEEK_OF_YEAR"
      , EXTRACT(DAY FROM start_date) AS "DAY"
      , TO_CHAR(start_date, 'DDD') AS "DAY_OF_YEAR"
      , TO_CHAR(start_date, 'DAY') AS "WEEKDAY"
      , TO_CHAR(start_date, 'Q') AS "QTR_OF_YEAR"
      , TO_CHAR(start_date, 'MONTH DD, YYYY') AS FRIENDLY
  FROM (SELECT TO_DATE('2008-12-31','YYYY-MM-DD') + level as start_date
        FROM   dual
        CONNECT BY level < 10000);

Oracle - 无法创建日期引用表

2 个答案: