PHP下载Zip

Question

我在特定路径中有一个文件.tar.gz。 路径记忆在变量$pathResult

中

使用此代码我可以下载文件：

header("Cache-Control: public");
header("Content-Description: File Transfer");
header("Content-Disposition: attachment; filename= " . trim($pathResult));
header("Content-Transfer-Encoding: binary");
readfile(trim($pathResult));

当我获取文件并且我证明要提取内容时，我收到如下错误：no archives identified为什么???

文件名是：SelectResult1.tar.gz 和$pathResult = "C:/wamp/www/prove/WORKSPACE/8c9d081f/SelectResult1.tar.gz"

Answer 1

使用它：

   $file='/path/file.ext';
    header("Cache-Control: public");
    header("Content-Description: File Transfer");
    header("Content-Disposition: attachment; filename=$file");
    header("Content-Type: application/zip");
    header("Content-Transfer-Encoding: binary");

    // read the file from disk
    readfile($file);