Question

我刚刚完成了这个大理石游戏程序的工作，它工作正常，除了我需要做一件事来保护它免受无效输入。程序正确响应所有基于整数的无效输入，但如果输入非整数，程序将崩溃。我一直在使用cin.fail（）函数，它可以工作，但然后陷入循环。如果用户输入非整数，我希望程序告诉用户输入无效并提示用户再次输入他们的选择。

我添加了返回1;在无效的输入语句之后结束程序而不是崩溃，但这不是我想要做的。我希望它打印“无效输入”，然后重新提示用户再次输入他们的选择。

#include <iostream>
using namespace std;

int main()
{
    cout << "*** The Game of Nim ***\n\n" << endl;

    string player1, player2, currentPlayer;
    int marbles, selection;
    bool isDone = false;

    cout << "Enter a name for Player 1: ";
    cin >> player1;
    cout << "Enter a name for Player 2: ";
    cin >> player2;
    cout << "Enter how many marbles you would like to start with in the pile: ";
    cin >> marbles;

    cout << "\nThere are " << marbles << " marbles in the pile\n" << endl;

    currentPlayer = player1;

    do
    {
        bool turnDone = false;

        while (turnDone == false && marbles != 0)
        {
            if (currentPlayer == player1)
            {
                cout << currentPlayer << "\n";

                cout << "How many marbles would you like to draw? : ";
                cin >> selection;

                if (cin.fail())
                {
                    cout << "\nInvalid Input\n";
                    return 1;

                }


                if (selection < marbles / 2 + 1 && marbles > 1 && selection != 0)
                {
                    marbles = marbles - selection;

                    if (marbles == 1)
                    {
                        cout << "\nUh Oh! There is only 1 marble remaining in the pile\n" << endl;

                        currentPlayer = player2;
                        turnDone = true;
                        break;
                    }

                    cout << "\nThere are " << marbles << " marbles remaining in the pile\n" << endl;

                    currentPlayer = player2;

                    turnDone = true;

                }else if (marbles == 1)
                {
                    marbles = marbles - selection;

                    if (marbles <= 0)
                    {
                        cout << "\nThere are 0 marbles remianing in the pile\n";

                        cout << "You drew the last marble!" << endl;
                        cout << "You lose!\n\n" << endl;
                        cout << player2 << " wins\n\n" << endl;

                        turnDone = true;

                        return 0;

                    }

                }else if (selection == 0 || selection > marbles / 2 + 1)
                {
                    cout << "\nYou must draw at least 1 marble, and no more than half the pile\n" << endl;
                }

            }else if (currentPlayer == player2)
            {
                cout << currentPlayer << "\n";

                cout << "How many marbles would you like to draw? : ";
                cin >> selection;

                if (selection < marbles / 2 +1 && marbles > 1 && selection != 0)
                {
                    marbles = marbles - selection;

                    if (marbles == 1)
                    {
                        cout << "\nUh Oh! There is only 1 marble remaining in the pile\n" << endl;

                        currentPlayer = player1;
                        turnDone = true;
                        break;
                    }

                    cout << "\nThere are " << marbles << " marbles remaining in the pile\n" << endl;

                    currentPlayer = player1;

                    turnDone = true;

                }else if (marbles == 1)
                {
                    marbles = marbles - selection;

                    if (marbles <= 0)
                    {
                        cout << "\nThere are 0 marbles remianing in the pile\n";

                        cout << "You drew the last marble!" << endl;
                        cout << "You lose!\n\n" << endl;
                        cout << player1 << " wins!\n\n" << endl;

                        turnDone = true;

                        return 0;

                    }

                }else if (selection == 0 || selection > marbles / 2 + 1)
                {
                    cout << "\nYou must draw at least 1 marble, and no more than half the pile\n" << endl;
                }
            }
        }
    }while (isDone == false);

    return 0;
}

Answer 1

以下是在程序中使用std :: cin.fail（）的方法：

int marbles;
bool check = false;
do {
    std::cout << "Enter how many marbles you would like to start with in the pile: ";
    std::cin >> marbles;
    if (std::cin.fail()) {
        std::cin.clear();
        std::cin.ignore();
    }
    else
        check = true;
}while(!check);

cin.fail（）将返回一个布尔说法是否已收到预期收入如果没有，你将不得不使用clear（）将失败值置为false然后忽略给定的输入
希望有所帮助

Answer 2

以字符串形式获取用户输入并检查其中是否有任何数字：

std::string input; 
std::cin >> input;
int marbles = std::atoi(input.c_str()); //Returns the first number met in the char table, if there is none, returns 0

if(marbles)
    std::cout << marbles;

初学者C ++使用cin.fail（）

2 个答案: