Question

我尝试在报告服务中返回ID和NUM的计数，其中包含用户输入的USERID和CREATION_DATE。我的目标是得到一行，包含两个计数。我得到了正确的计数，但是我显示了几行回报。（具有用户指定参数的行）。如何只获得一行只包含COUNTID和COUNTNUM字段的行。我使用的是Microsoft SQL Server。

SELECT

     (SELECT COUNT(ID)
        FROM   PART
        WHERE  USERID = $P{userId} and CREATION_DATE = $P{creationDate}) as COUNTID ,
  (SELECT COUNT(NUM)
        FROM   IDENTITY
        WHERE  USERID = $P{userId}  and CREATION_DATE = $P{creationDate}) as COUNTNUM 
FROM
      PART,
      IDENTITY

Answer 1

如果您只想返回一行，并且每个子查询都返回＆＃34; count＆＃34;你想要的，你可以从外部查询中删除// Radio buttons for PEOPLE $('input[name="wccf[product][people]"]').on('click', function() { $(".checked").removeClass("checked"); $(this).parent().toggleClass("checked"); }); // Radio buttons for BUDGET $('input[name="wccf[product][budget]"]').on('click', function() { $(".checked").removeClass("checked"); $(this).parent().toggleClass("checked"); });子句。像这样：

FROM

就个人而言，我的查询方式略有不同。我将子查询用作FROM子句中交叉连接的内联视图，每个内联视图都返回一行。像这样：

  SELECT ( SELECT COUNT(p.ID)
             FROM PART p
            WHERE p.USERID        = $P{userId}
              AND p.CREATION_DATE = $P{creationDate}
         ) AS COUNTID
       , ( SELECT COUNT(i.NUM)
             FROM IDENTITY i
            WHERE i.USERID        = $P{userId}
              AND i.CREATION_DATE = $P{creationDate}
         ) AS COUNTNUM

Answer 2

使用联接和分组依据 - 如下所示：

SELECT P.USERID, P.CREATION_DATE, COUNT(P.ID) AS COUNTID, COUNT(I.NUM) AS COUNTNUM
FROM PART P
JOIN IDENTITY I ON P.USERID = I.USERID AND P.CREATION_DATE = I.CREATION_DATE
WHERE P.USERID = $P{userId}  and P.CREATION_DATE = $P{creationDate}
GROUP BY P.USERID, P.CREATION_DATE

如果您取出WHERE，则可以看到所有用户和所有日期的结果。

注意，如果并非所有用户和日期都在PART表或Identity表中，请执行以下操作：

SELECT B.USERID, B.CREATION_DATE, COUNT(P.ID) AS COUNTID, COUNT(I.NUM) AS COUNTNUM
FROM (
   SELECT DISTINCT USERID, CREATEION_DATE FROM PART
    UNION 
   SELECT DISTINCT USERID, CREATEION_DATE FROM IDENTITY
) AS B
LEFT JOIN PART P ON B.USERID = P.USERID AND B.CREATION_DATE = P.CREATION_DATE
LEFT JOIN IDENTITY I ON B.USERID = I.USERID AND B.CREATION_DATE = I.CREATION_DATE
WHERE B.USERID = $P{userId}  and B.CREATION_DATE = $P{creationDate}
GROUP BY B.USERID, B.CREATION_DATE

注意：第二个查询多更正确，但根据您的数据可能不需要。 由于您没有告诉我们您的数据或数据模型，我很难知道第一个查询是否有效。

SQL查询语法正确

2 个答案: