Question

我正试图离开entity_id，但只收到一个没有细节的错误。

Drupal中的entity_id是否有一个技巧？

$query = db_query('SELECT COUNT(n.field_feed_vehicle_code_value) FROM {field_data_field_feed_vehicle_code} n LEFT JOIN {field_data_field_feed_vehicle_date_used} du ON n.entity_id = du.entity_id WHERE n.field_feed_vehicle_code_value = :utilization AND du.field_feed_vehicle_date_used = :utilization_date', array(':utilization' =>  $fieldVehicleCode, ':utilization_date' =>  $fieldDVIRDate))->fetchField();

我发现了其他关于leftjoins的问题，但实际上没有关于entity_id的问题。我也发现了这个Drupal 7 select query with joins但是这个解决方案也没有用。

$query = db_select('node', 'n');
$query->leftJoin('field_data_field_feed_vehicle_code', 'vc', 'n.nid =   vc.entity_id');
$query->leftJoin('field_data_field_feed_vehicle_date_used', 'du', 'n.nid = du.entity_id');
$query
->fields('n', array('nid'))
->fields('vc.field_feed_vehicle_code_value', $fieldVehicleCode , '=')
->fields('du.field_feed_vehicle_date_used', $fieldDVIRDate , '=')
->condition('type', 'dvir_utilization_feed')
->condition('status', 1)
->execute();
$num = $query->rowCount();

Answer 1

我相信你想用

->condition('vc.field_feed_vehicle_code_value', $fieldVehicleCode , '=')
->condition('du.field_feed_vehicle_date_used', $fieldDVIRDate , '=')

因为这不是->fields

的正确语法

Answer 2

我最终得到了错误的字段名称并且必须执行db_query，尽管我更喜欢db_select。

$query = db_query('SELECT COUNT(vc.field_feed_vehicle_code_value)
                                  FROM {node} n 
                                  LEFT JOIN {field_data_field_feed_vehicle_code} vc ON n.nid = vc.entity_id
                                  LEFT JOIN {field_data_field_feed_vehicle_date_used} du ON n.nid = du.entity_id
                                  WHERE vc.field_feed_vehicle_code_value = :utilization 
                                     AND du.field_feed_vehicle_date_used_value = :utilization_date', 
                                  array(':utilization' =>  $fieldVehicleCode, ':utilization_date' =>  $fieldDVIRDate))->fetchField();


            $utilization = $query;

Drupal 7选择带有entity_id连接的查询

2 个答案: