Question

我需要帮助实现一个while循环，它将用户输入作为double或int（不确定）并将其作为平方根，直到它达到小于或等于1.01。

示例：Math.sqrt(10.5)

1. Calculated square root is --> 3.24037034920393
2. Calculated square root is --> 1.8001028718392542
3. Calculated square root is --> 1.3416791240230483
4. Calculated square root is --> 1.1583087343290857
5. Calculated square root is --> 1.0762475246564267
6. Calculated square root is --> 1.0374235030383814
7. Calculated square root is --> 1.0185398877993839

import java.util.Scanner;
public class SquareRoot {

    public static void main (String args[]){
        final double SENTINEL = 10;
        int count = 0;

        Scanner scan = new Scanner(System.in);
        double userInput; // input value

        do
        {
            System.out.println( "Enter a number greater than 10"  );
            userInput = scan.nextDouble( );
        } while ( userInput <= 1 || userInput >= 10 );


        double squareRoot = Math.sqrt(userInput);
        double resultSquareRoot = Math.sqrt(squareRoot);

        while (resultSquareRoot <= 1.01){
            resultSquareRoot = Math.sqrt(squareRoot);

        }
        System.out.println(resultSquareRoot);


    }

}

Answer 1

你的循环：

while (resultSquareRoot <= 1.01){
    resultSquareRoot = Math.sqrt(squareRoot);
}
System.out.println(resultSquareRoot);

应该是：

while (resultSquareRoot > 1.01){
    System.out.println("Calculated square root is --> " + resultSquareRoot);
    resultSquareRoot = Math.sqrt(resultSquareRoot);
}

您不会将参数的值更改为Math.sqrt，因此resultSquareRoot永远不会更改。

您想要resultSquareRoot = Math.sqrt(resultSquareRoot);

而不是resultSquareRoot = Math.sqrt(squareRoot);

Answer 2

您的解决方案中很少有注意事项，为什么尝试在do-while中调用以下代码行。不需要，因为你的意图是应用Math.sqrt，直到输入的数字方块达到1.01，因此我们在谈论循环。

System.out.println（“输入一个大于10的数字”）; userInput = scan.nextDouble（）;

此外，您不需要第二次while循环。

while (resultSquareRoot <= 1.01){
            resultSquareRoot = Math.sqrt(squareRoot);

        }

代码中缺少的是中断条件。

这可以通过以下代码行来实现。

    do {
         userInput = Math.sqrt(userInput);
        System.out.println("Calculated square root is -->"+userInput);
        if(userInput<= 1.01)
            break;
    } while (userInput >= 1.01 );

输出

Calculated square root is -->3.24037034920393
Calculated square root is -->1.8001028718392542
Calculated square root is -->1.3416791240230483
Calculated square root is -->1.1583087343290857
Calculated square root is -->1.0762475246564267
Calculated square root is -->1.0374235030383814
Calculated square root is -->1.0185398877993839
Calculated square root is -->1.0092273717053972

Answer 3

您可能想要更改

 while (resultSquareRoot <= 1.01){
        resultSquareRoot = Math.sqrt(squareRoot);

    }

到

 while (resultSquareRoot > 1.01){
        resultSquareRoot = Math.sqrt(resultSquareRoot );

    }

Answer 4

do while条件错误。它应该是：

do
    {
     System.out.println( "Enter a number greater than 10"  );
     userInput = scan.nextDouble( );
    } while ( userInput <= 10 );

而while条件也是错误的。请检查下面的代码：

public static void main (String args[]){
        final double SENTINEL = 10;
        int count = 0;

        Scanner scan = new Scanner(System.in);
        double userInput; // input value

        do
        {
            System.out.println( "Enter a number greater than 10"  );
            userInput = scan.nextDouble( );
        } while ( userInput <= 10 );

        double resultSquareRoot = userInput;

        while (resultSquareRoot >= 1.01){
            resultSquareRoot = Math.sqrt(resultSquareRoot);

        }
        System.out.println(resultSquareRoot);


    }

Answer 5

您要求的数字大于10，所以您应该

do
{
    System.out.println( "Enter a number greater than 10"  );
    userInput = scan.nextDouble( );
} while ( userInput < 10 );

因为你想要一个小于10的数字。

然后在这里，您始终执行Math.sqrt(squareRoot)并将其存储在resultSquareRoot中，因此您在while循环内的resultSquareRoot内始终获得相同的值，因为你永远不会改变squareRoot的价值。并且您希望您的条件运行while it is greater than 1.01

double squareRoot = Math.sqrt(userInput);
double resultSquareRoot = Math.sqrt(squareRoot);

while (resultSquareRoot > 1.01){
    resultSquareRoot = Math.sqrt(resultSquareRoot);
}
System.out.println(resultSquareRoot);

while循环找到一个数字的平方根，直到它小于或等于1.01

5 个答案:

输出