Question

我想在R中绘制分段数据。也就是说，我有格式

的数据

| Product               | Date   | Origination | Rate | Num | Balance   |
|-----------------------|--------|-------------|------|-----|-----------|
| DEMAND DEPOSITS       | 200505 | 198209      | 0    | 1   | 2586.25   |
| DEMAND DEPOSITS       | 200505 | 198304      | 0    | 1   | 3557.73   |
| DEMAND DEPOSITS       | 200505 | 198308      | 0    | 1   | 14923.72  |
| DEMAND DEPOSITS       | 200505 | 198401      | 0    | 1   | 4431.67   |
| DEMAND DEPOSITS       | 200505 | 198410      | 0    | 1   | 44555.23  |
| MONEY MARKET ACCOUNTS | 200505 | 198209      | 0.25 | 2   | 65710.01  |
| MONEY MARKET ACCOUNTS | 200505 | 198211      | 0.25 | 2   | 41218.41  |
| MONEY MARKET ACCOUNTS | 200505 | 198304      | 0.25 | 1   | 61421.2   |
| MONEY MARKET ACCOUNTS | 200505 | 198402      | 0.25 | 1   | 13620.17  |
| MONEY MARKET ACCOUNTS | 200505 | 198408      | 0.75 | 1   | 281897.74 |
| MONEY MARKET ACCOUNTS | 200505 | 198410      | 0.25 | 1   | 5131.33   |
| NOW ACCOUNTS          | 200505 | 198209      | 0    | 1   | 142744.35 |
| NOW ACCOUNTS          | 200505 | 198303      | 0    | 1   | 12191.6   |
| SAVING ACCOUNTS       | 200505 | 198301      | 0.25 | 1   | 96936.24  |
| SAVING ACCOUNTS       | 200505 | 198302      | 0.25 | 2   | 21764     |
| SAVING ACCOUNTS       | 200505 | 198304      | 0.25 | 1   | 14646.55  |
| SAVING ACCOUNTS       | 200505 | 198305      | 0.25 | 1   | 20909.7   |
| SAVING ACCOUNTS       | 200505 | 198306      | 0.25 | 1   | 66434.56  |
| SAVING ACCOUNTS       | 200505 | 198309      | 0.25 | 1   | 20005.56  |
| SAVING ACCOUNTS       | 200505 | 198404      | 0.25 | 2   | 16766.56  |
| SAVING ACCOUNTS       | 200505 | 198407      | 0.25 | 1   | 47721.97  |

我想在Y轴上绘制一条线＆＃39; Product＆＃39;输入＆＃39;余额＆＃39;。在X轴上，我想提出“起源”。理想情况下，我也想设置颜色来区分线条。数据当前不是 data.frame 形式，所以如果我需要更改回来，请告诉我。

我已经无法在网上找到一个信息丰富的解决方案，即使我确定有。

谢谢，

Answer 1

正如@ zx8754所说，你应该提供可重复的数据。没有测试代码（因为没有可重现的数据），我建议如下，假设数据在data.frame'数据'中：

all_products <- unique(data$Product)
colors_use <- rainbow(length(all_products))

plot(y = data[data$Product == all_products[1],"Balance"],
    x = data[data$Product == all_products[1],"Origination"],
    type = "l",
    col = colors_use[1],
    ylim = c(min(data$Balance, na.rm = T),max(data$Balance, na.rm = T)),
    xlim = c(min(data$Origination, na.rm = T),max(data$Origination, na.rm = T)))

for(i_product in 2:length(all_products)){
    lines(y = data[data$Product == all_products[i_product],"Balance"],
        x = data[data$Product == all_products[i_product],"Origination"],
        col = colors_use[i_product])
}

Answer 2

我没有足够的声誉来评论，所以我把它写成答案。为了缩短@ tobiasegli_te的答案，第一个plot可以是plot(Balance~Origination,data=data,type='n')，然后为lines完成后续的i_product in 1:length(all_products)。这样你就不必担心ylim了。以下是使用Grunfeld数据的示例。

z <- read.csv('http://statmath.wu-wien.ac.at/~zeileis/grunfeld/Grunfeld.csv')
plot(invest~year,data=z,type='n')
for (i in unique(as.numeric(z$firm))) lines(invest~year,data=z,
    subset=as.numeric(z$firm)==i, col=i)

另请注意，Origination的间隔不均等。您需要将其更改为Date或类似。

Answer 3

我想你想要的东西如下：

df <- as.data.frame(df[c('Product', 'Balance', 'Origination')])
head(df)

Product  Balance Origination
1  DEMAND DEPOSITS         2586.25      198209
2  DEMAND DEPOSITS         3557.73      198304
3  DEMAND DEPOSITS        14923.72      198308
4  DEMAND DEPOSITS         4431.67      198401
5  DEMAND DEPOSITS        44555.23      198410
6  MONEY MARKET ACCOUNTS  65710.01      198209

library(ggplot2)
library(scales)
ggplot(df, aes(Origination, Balance, group=Product, col=Product)) + 
         geom_line(lwd=1.2) + scale_y_continuous(labels = comma)

Answer 4

我不确定你想要的是什么，是你在寻找什么？

假设您将数据放在data.txt中，删除管道并用＆＃39; _＆＃39;

替换名称中的空格

d = read.table("data.txt", header=T)

prod.col = c("red", "blue", "green", "black" )
prod = unique(d$Product)

par(mai = c(0.8, 1.8, 0.8, 0.8))
plot(1, yaxt = 'n', type = "n", axes = TRUE, xlab = "Origination", ylab = "", xlim = c(min(d$Origination), max(d$Origination)), ylim=c(0, nrow(d)+5) )
axis(2, at=seq(1:nrow(d)), labels=d$Product, las = 2, cex.axis=0.5)
mtext(side=2, line=7, "Products")

for( i in 1:nrow(d) ){
myProd = d$Product[i]
myCol = prod.col[which(prod == myProd)]
myOrig  = d$Origination[i]
segments( x0 = 0, x1 = myOrig, y0 = i, y1 = i, col = myCol, lwd = 5 )
}
legend( "topright", col=prod.col, legend=prod, cex=0.3, lty=c(1,1), bg="white" )

在R中绘制段图

4 个答案: