Question

在SQL Server中，我希望从日期到日期获得好几天。示例：从2015/12/28到2016/01/02，结果为

2015/12/28
2015/12/29
2015/12/30
2015/12/31
2016/01/01
2016/01/02

DECLARE @STARTDATE DATETIME = '2015-12-28'
DECLARE @ENDDATE DATETIME = '2016-01-02'
SELECT BETWEEN @STARTDATE AND @ENDDATE AS DAYS

Answer 1

使用 CTE

DECLARE @STARTDATE DATE = '2015-12-28'
DECLARE @ENDDATE DATE = '2016-01-02'

;WITH CTE AS
(
   SELECT @STARTDATE As dt
   UNION ALL
   SELECT DATEADD(D,1,dt) AS dt
   FROM CTE
   WHERE dt < @ENDDATE   
)
SELECT * FROM CTE

Answer 2

You could build a calendar table，这可能会派上用场。或者你可以使用循环。

DECLARE @ENDDATE DATETIME = '2016-01-02'
DECLARE @DAY DATETIME = '2015-12-28'
WHILE @Day <= @ENDDATE
BEGIN
SELECT @DAY
SET @DAY = DATEADD(DD,1,@DAY)
END

或者在一个结果集中的所有日子：

DECLARE @ENDDATE DATETIME = '2016-01-02'
DECLARE @DAY DATETIME = '2015-12-28'
DECLARE @TABLE TABLE (DATE DATETIME)
WHILE @Day <= @ENDDATE
BEGIN
INSERT @TABLE
VALUES (@DAY)
SET @DAY = DATEADD(DD,1,@DAY)
END

SELECT *
FROM @TABLE

Answer 3

您可以在WHERE子句中指定日期。例如，WHERE日期＆gt; = @ STARTDATE和日期＆lt; = @ ENDDATE。这应该返回结果中的完整日期。

Answer 4

使用Numbers表

dict.__len__

如何在SQL Server中获取从日期到日期的日期？

4 个答案: