Question

此时下面列出的代码，作为在whmcs中使用它的一部分

                                {php}
                        $cleansed_uid = (int) $_SESSION['uid'];
                        $query = "SELECT * FROM tblhosting WHERE userid=".mysql_escape_string($cleansed_uid)." AND (domainstatus='Active') AND (packageid='10' OR packageid='2' OR packageid='30' OR packageid='40' OR packageid='44' OR packageid='45' OR packageid='104' )";
                        $result = mysql_query($query);
                        $total = mysql_num_rows($result);
                        while ($data = mysql_fetch_array($result)) {
                        echo "$total";
                        }
                    {/php}

但我的结果是22，而不是2，或333而不是3 query results

我想要做的是，根据用户ID获取活动服务并与软件包xyq匹配，并根据软件包显示为总活动服务，如您所见;我能够获取信息，只是总数是错误的，请指出我正确的方法来做到这一点。感谢。

Answer 1

while ($data = mysql_fetch_array($result)) {
                        $total = mysql_num_rows($result);

更改为

 $total = mysql_num_rows($result);
   while ($data = mysql_fetch_array($result)) {

站在外线：

echo "$total";

总数：

$cleansed_uid = (int) $_SESSION['uid'];
                        $query = "SELECT * FROM tblhosting WHERE userid=".mysql_escape_string($cleansed_uid)." AND (domainstatus='Active') AND (packageid='1' OR packageid='20' OR packageid='30' OR packageid='40' OR packageid='44' OR packageid='45' OR packageid='104' )";
                        $result = mysql_query($query);
                        $total = mysql_num_rows($result);
                        while ($data = mysql_fetch_array($result)) {
                        $id = $data["id"];
                        $domain = $data["dedicatedip"];
}
                            echo "$total";

mysql查询计数显示结果一次

1 个答案: