我希望在QApplication :: notify例程中捕获未捕获的异常以正常关闭。但应用程序崩溃
我在Windows上使用Qt 5.6,mingw 5.3.0 x64。
任何想法我做错了什么?
#include <QApplication>
#include <QObject>
#include <QtDebug>
#include <QTimer>
class TestApplication Q_DECL_FINAL : public QApplication
{
Q_OBJECT
public:
TestApplication(int &argc, char **argv) : QApplication(argc, argv) {}
bool notify(QObject *receiver, QEvent *event) {
try {
return QApplication::notify(receiver, event);
} catch(std::exception& e) {
qCritical() << qPrintable(QString("Exception thrown: %1").arg(e.what()));
}
return false;
}
};
#include "main.moc"
int main(int argc, char *argv[])
{
TestApplication a(argc, argv);
QTimer timer;
timer.setSingleShot(true);
QObject::connect(&timer, &QTimer::timeout, []() {
throw 1;
});
timer.start(5000);
return a.exec();
}
答案 0 :(得分:1)
尝试使用实际的异常对象而不是int。喜欢&#39;抛出std :: exception()&#39;。适用于Qt 5.7 Mingw Win10。