Question

我是脚本新手，想了解如何根据布尔逻辑打印出变量。

None

如果两个部分都成功，我希望整个#!/bin/bash # set variables WEBAPPS_YES="Successfully synced webapps folder" WEBAPPS_NO="Could not sync webapps folder" RSYNC_YES="Successfully synced rsync log file" RSYNC_NO="Could not sync rsync log file" # Command to rsync 'webapps' folder and write to a log file rsync -azvh ~/webapps -e ssh user@something.com:/home/directories >> /path/to/rsync.log 2>&1 # Command to rsync 'rsync.log' to a log file on backup server 'Larry' rsync -azvh --delete ~/rsync.log -e ssh user@something.com:/path/to/logs if [ $? -eq 0 ] then echo exit 0 else echo >&2 exit 1 fi，if，then部分在else打印出来。我知道我需要某种逻辑陈述，但无法弄明白。

Answer 1

您可以在运行每个rsync命令后检查结果，然后显示结果。我认为这样可行：

# Command to rsync 'webapps' folder and write to a log file
rsync -azvh ~/webapps -e ssh user@something.com:/home/directories >> /path/to/rsync.log 2>&1
RESULT1="$?"

# Command to rsync 'rsync.log' to a log file on backup server 'Larry'
rsync -azvh --delete ~/rsync.log -e ssh user@something.com:/path/to/logs
RESULT2="$?"

if [ "$RESULT1" != "0" ]; then
    echo "$WEBAPPS_NO"
else
    echo "$WEBAPPS_YES"
fi

if [ "$RESULT2" != "0" ]; then
    echo "$RSYNC_NO"
else
    echo "$RSYNC_YES"
fi

运行2个rsync命令并将输出打印到日志文件

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