Question

我在过去的两个月里一直在尝试编写脚本！很多学习！由于我在这方面完全是新手，我很想知道你是否可以帮助我！

看，我刚刚完成了一个JSON（一个大的），这与我在这里的内容很接近

[{
"League": "English Championship",
"Champion": "Team 4",
"Vice": "Team 3",
"Third": "Team 1",
}, {
"League": "European Championship",
"Champion": "Team 3",
"Vice": "Team 2",
"Third": "Team 1
}]

我想计算一个特定团队在元素'冠军'，'副'和'第三'中出现的次数，所以我可以创建这样的东西：

______|_1st_|_2nd_|_3rd_
Team 1|__0__|__0__|__2__|
Team 2|__0__|__1__|__0__|
Team 3|__1__|__1__|__0__|
Team 4|__1__|__0__|__0__|

当我正在研究JS和jQuery时，我想知道是否可以为这个表开发一个新的数组。如果它真的很难，我可以使用excel来表示所有内容，然后再次进入JSON。

我只想要一个开头小费！

谢谢

Answer 1

您可以使用Array.prototype.reduce()，for..in循环。请注意，"

时缺少结束"Third": "Team 1

var data = [{
  "League": "English Championship",
  "Champion": "Team 4",
  "Vice": "Team 3",
  "Third": "Team 1",
}, {
  "League": "European Championship",
  "Champion": "Team 3",
  "Vice": "Team 2",
  "Third": "Team 1"
}];

var res = data.reduce(function(obj, b, index) {
  if (!index) { // if `index` is equal to `0`
    for (var prop in b) { // iterate properties of `b` object in `data` array
      if (prop !== "League") { // exclude `"League"` from next block
        // set `obj` : `{}` set at third parameter to `.reduce()`
        // property to `b[prop]`, value to `1`
        obj[prop] = {[b[prop]]:1}; 
      }
    }
  } else {
    for (var prop in obj) { // iterate properties of `obj` object
      if (obj[prop][b[prop]]) { // if `obj[prop][b[prop]]` property is defined
          ++obj[prop][b[prop]]; // increment value
      }
    }
  };
  return obj // return `obj`
}, {});

console.log(res);

Answer 2

您可以使用Array.prototype.filter()

data = [{
    "League": "English Championship",
    "Champion": "Team 4",
    "Vice": "Team 3",
    "Third": "Team 1",
}, {
    "League": "European Championship",
    "Champion": "Team 3",
    "Vice": "Team 2",
    "Third": "Team 1"
}]

function getCount(position, team) {
    return data.filter(function(x) {
        return x[position] == team
    }).length
}

console.log(getCount('Champion', 'Team 1'))
console.log(getCount('Vice', 'Team 1'))
console.log(getCount('Third', 'Team 1'))
console.log(getCount('Champion', 'Team 2'))
console.log(getCount('Vice', 'Team 2'))
console.log(getCount('Third', 'Team 2'))
console.log(getCount('Champion', 'Team 3'))
console.log(getCount('Vice', 'Team 3'))
console.log(getCount('Third', 'Team 3'))

Answer 3

您可以使用Array.prototype.reduce()获取您想要的数据结构

＆＃13;

const json = [{
    "League": "English Championship",
    "Champion": "Team 4",
    "Vice": "Team 3",
    "Third": "Team 1"
}, {
    "League": "European Championship",
    "Champion": "Team 3",
    "Vice": "Team 2",
    "Third": "Team 1"
}];

const sum = json.reduce(function (next, res) {
    const initObj = () => ({
        "Champion": 0,
        "Vice": 0,
        "Third": 0
    });

    if(!next[res["Champion"]]) {
        next[res["Champion"]] = initObj();
    }

    if (!next[res["Vice"]]) {
        next[res["Vice"]] = initObj();
    }

    if (!next[res["Third"]]) {
        next[res["Third"]] = initObj();
    }

    next[res["Champion"]]["Champion"] += 1;
    next[res["Vice"]]["Vice"] += 1;
    next[res["Third"]]["Third"] += 1;
    return next;
}, {});

console.log(sum);

＆＃13;

我可以计算名称在JSON中的特定基因座中出现的次数吗？

3 个答案: