Question

我正在使用PHP创建一个MYSQL数据库及其表格，其中插入了值。我希望使用相同的PHP文件创建数据库及其表。由于某种原因，未创建数据库及其表。如何一次创建数据库及其表？非常感谢，这是下面的代码：

<?php
$servername = "localhost";
$username = "root";
$password = "";

// Create database
$sql = "CREATE DATABASE school";
if (mysqli_query($conn, $sql)) {
    echo "Database created successfully";
} else {
    echo "Error creating database: " . mysqli_error($conn);
}

mysqli_close($conn);

$dbname = "school"; //database name

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}    


$sql = CREATE TABLE student (
  'id' int(6) NOT NULL AUTO_INCREMENT,
  'name' varchar(500) NOT NULL,
  'gender' varchar(100) NOT NULL,
  PRIMARY KEY ('id');

INSERT INTO 'student' ('id', 'name', 'gender') VALUES
(1, 'Cassidy Jackson', 'female'),
(2, 'jack Hilson', 'male');

if (mysqli_query($conn, $sql)) {
    echo "Table school created successfully";
} else {
    echo "Error creating table: " . mysqli_error($conn);
}

mysqli_close($conn);
?>

Answer 1

你有很多错误。您不打开连接但尝试创建数据库。在此之后，您关闭不存在的连接等。但您的SQL也有错误。首先，它们不是php的字符串，永远不会使用列或表名的单引号，仅用于值。

您的代码

<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "";
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Create database
$sql = "CREATE DATABASE school";
if (mysqli_query($conn, $sql)) {
    echo "Database created successfully<br>";
} else {
    echo "Error creating database: " . mysqli_error($conn) . "<br>";
}

mysqli_select_db ( $conn , "school" );

 //database name

// Create connection

// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}    


$sql = "CREATE TABLE `school` (
  `id` INT NOT NULL AUTO_INCREMENT,
  `name` VARCHAR(500) NOT NULL,
  `gender` VARCHAR(100) NOT NULL,
  PRIMARY KEY (`id`),
   UNIQUE INDEX `idschool_UNIQUE` (`id` ASC));";
if(mysqli_query($conn, $sql)){
    echo "Table school created successfully<br>";
} else {
    echo "Error creating table: " . mysqli_error($conn). "<br>";
}

$sql = "INSERT INTO `student` (id, name, gender) VALUES
(1, 'Cassidy Jackson', 'female'),
(2, 'jack Hilson', 'male')";

if (mysqli_query($conn, $sql)) {
    echo "Values Inserted successfully<br>";
} else {
    echo "Error ınsert values to table: " . mysqli_error($conn) . "<br>";
}

mysqli_close($conn);
?>

在同一文件中同时创建MYSQL数据库及其表

1 个答案:

您的代码