我们逐步开展了一个项目。最后一个里程碑将此划分为以下内容:使用以下四种方法创建一个类:main方法,创建客户信息的方法(void),创建用户名和密码的方法(void)以及最后登录方法(返回类型)。
我已经实现了登录方法,当转移到loginDetails
的实现时,我遇到了问题。我不明白如何在void方法中创建loginDetails
,并且还能够以不同的方法检查它。我的loginDetail
方法没有向main返回值,我的变量是方法的本地变量。
如何在void方法中创建用户详细信息,并能够在单独的方法中创建登录检查?
这是我的代码,我想使用loginDetails();
中生成的详细信息作为要检查的值,而不是手动插入的字符串。
public class Customer {
static Scanner input = new Scanner(System.in);
public static void main(String[] args) {
loginDetails("testtest", "testtest", "11111121111");
System.out.print(logIn("ABC", "212"));
}
public static void customerInformation() {
//Create customerInformation
}
public static void loginDetails(String firstName, String lastName, String number) {
String userName, password;
userName = firstName.charAt(0) + lastName.substring(0, 3);
password = lastName.substring(0, 3) + number.substring(7);
}
public static String logIn(String userName, String password) {
int count = 0;
while (count < 3) {
System.out.print("Input Username");
String inputUserName = input.nextLine();
System.out.print("Input password");
String inputPassword = input.nextLine();
if (inputUserName.equals(userName) && inputPassword.equals(password)) {
return "You are now logged in";
} else {
count++;
if (count < 3)
System.out.println("Wrong Username or password. Try again");
}
} //While
return "Try again in a few hours"; //Third try
} //logIn
}
答案 0 :(得分:0)
class Customer {
static Scanner input = new Scanner(System.in);
static String userName=null;
static String password=null;
public static void main(String[] args) {
loginDetails("testtest", "testtest", "11111121111");
System.out.print(logIn("ABC", "212"));
}
public static void customerInformation() {
//Create customerInformation
}
public static void loginDetails(String firstName, String lastName, String number) {
userName = firstName.charAt(0) + lastName.substring(0, 3);
password = lastName.substring(0, 3) + number.substring(7);
}
public static String logIn(String userName, String password) {
int count = 0;
while (count < 3) {
System.out.print("Input Username");
String inputUserName = input.nextLine();
System.out.print("Input password");
String inputPassword = input.nextLine();
if (inputUserName.equals(userName) && inputPassword.equals(password)) {
return "You are now logged in";
} else {
count++;
if (count < 3)
System.out.println("Wrong Username or password. Try again");
}
} //While
return "Try again in a few hours"; //Third try
} //logIn
}