周五我问过this question,从那以后我一直在努力尝试一切没有成功的事情
我无法让这个工作
SELECT * FROM WorldFlowers_table GROUP BY device_id ORDER BY score DESC LIMIT 100
然后回复我:
排名前100位的100行
已过滤,因此只显示每个device_id的最高得分
ORDER BY得分DESC
@ 1000111和Giorgos Betsos
一个人走进一个房间说,“请帮助,我疯狂地试图用我所有的力量解决一个简单的问题,任何人都可以在眨眼之间解决这个问题”
2个家伙转过身,射击脸上的那个人说“重复”
我筋疲力尽:(
///////// 来评论草莓评论
我尝试在SQLFiddle中构建它
CREATE TABLE WorldFlowers_table
(
id int identity primary key,
timestamp varchar(20),
name varchar(30),
score int,
color varchar(30),
flower varchar(30),
device_id varchar(30),
);
INSERT INTO WorldFlowers_table
(timestamp, name,score, color, flower, device_id )
VALUES
('1475151826', 'RI-RI', 42, '0|0|0|0|0|0|0|0|0|0', '[1475152768|42|4|0.0]', 'XYZ' ),
('1475151826', 'RO-RO', 46, '0|0|0|0|0|0|0|0|0|0', '[1475152768|42|4|0.0]', 'ABC' ),
('1475151826', 'RI-RI', 42, '0|0|0|0|0|0|0|0|0|0', '[1475152768|42|4|0.0]', 'XYZ' ),
('1475151826', 'RA-RA', 45, '0|0|0|0|0|0|0|0|0|0', '[1475152768|42|4|0.0]', 'ABC' ),
('1475151826', 'RU-RU', 42, '0|0|0|0|0|0|0|0|0|0', '[1475152768|42|4|0.0]', 'XYZ' ),
('1475151826', 'RE-RE', 44, '0|0|0|0|0|0|0|0|0|0', '[1475152768|42|4|0.0]', 'DEF' ),
('1475151826', 'RY-RY', 42, '0|0|0|0|0|0|0|0|0|0', '[1475152768|42|4|0.0]', 'XYZ' ),
('1475151826', 'RX-RX', 43, '0|0|0|0|0|0|0|0|0|0', '[1475152768|42|4|0.0]', 'XYZ' ),
('1475151826', 'RA-RA', 42, '0|0|0|0|0|0|0|0|0|0', '[1475152768|42|4|0.0]', 'DEF' );
但是只会在2中构建一次。
我正在寻找的回报将是
+------+------------+--------------------------------------------+
| id | timestamp | name | score | color | flower | device_id |
+------+------------+--------------------------------------------+
| 2 | blabla | RO-RO | 46 | ... | ... | ABC |
| 5 | blabla | RE-RE | 44 | ... | ... | DEF |
| 7 | blabla | RX-RX | 43 | ... | ... | XYZ |
+------+-------+-------------------------------------------------+
。每次返回每个设备ID只有1个
。每个设备ID得分最高
。并且结果在ORDER BY得分DESC中给出
更新:来自scaisEdge的这个似乎工作正常
SELECT * FROM分数
WHERE(名称,分数)IN(SELECT name,MAX(score)
来自分数
GROUP BY名称
ORDER BY得分DESC
)
ORDER BY得分DESC
限制100;
答案 0 :(得分:0)
如果我不正确你想要前100名设备得分
for sha in $(git log --format=%H); do
author="$(git show --format=%an $sha | head -n1)"
removed_if_statements=$(git show $sha | grep -E '^\-(.* )?if \(' | wc -l)
added_if_statements=$(git show $sha | grep -E '^\+(.* )?if \(' | wc -l)
delta=$(( $added_if_statements - $removed_if_statements ))
if [ $delta -gt 0 ]; then
for x in $(seq 1 $delta); do
echo $author
done
fi
done | sort | uniq -c | sort -rg
答案 1 :(得分:0)
MySQL在某些子查询运算符的子查询中不支持LIMIT:
[Branches.Branch_Employee].[endDate] IS NULL
https://dev.mysql.com/doc/mysql-reslimits-excerpt/5.6/en/subquery-restrictions.html
看看这里:
答案 2 :(得分:0)
SELECT id, timestamp, name, score, color, flower, device_id
FROM WorldFlowers_table
WHERE (device_id, score) IN
(SELECT device_id, MAX(score) FROM WorldFlowers_table GROUP BY device_id)
ORDER BY score DESC LIMIT 100;