Question

我在尝试将数据发布到CodeIgniter时遇到了一些问题，我有这个。

的Ajax

$.ajax({
            url: $('#url').val() + "Dashboard/Index",
            dataType: 'json',
            contentType: 'application/json',
            type: 'post',
            data: {data: data},
            success: function( data ){
              console.log(data);
            },
            error: function( jqXhr, textStatus, errorThrown ){
              console.log(jqXhr);
              console.log(textStatus);
              console.log( errorThrown );
            }
        });

控制器| Dashboard.php - ＆gt; class：Dashboard，function：index

atm我正在尝试用它来查看是否有发布的内容，但没有！

if($_POST) {
            print_r($_POST);
            die();
        }

所以我的整个控制器看起来像这样......

<?php
defined('BASEPATH') OR exit('No direct script access allowed');

class Dashboard extends CI_Controller 
    public function index()
    {

        // $test = $_POST['data'];
        // echo json_encode($_POST);
        if($_POST) {
            print_r($_POST);
            die();
        }


//////////////////////////////////Views///////////////////////////////// 



    // includes
    $data['footer'] = $this->load->view('includes/footer', NULL, TRUE);

    // App
    $data['menuProfile'] = $this->load->view('app/menuProfile', NULL, TRUE);
    $data['sidebarMenu'] = $this->load->view('app/sidebarMenu', NULL, TRUE);
    $data['topNavigation'] = $this->load->view('app/topNavigation', NULL, TRUE);
    $data['menuFooter'] = $this->load->view('app/menuFooter', NULL, TRUE);

    // Dashboard

    $dashboard['dinp'] = $this->load->view('app/dashboard/dinp', NULL, TRUE);
    $dashboard['dispTitle'] = $this->load->view('app/dashboard/dispTitle', NULL, TRUE);
    $dashboard['porcentaje'] = $this->load->view('app/dashboard/porcentaje', NULL, TRUE);
    $dashboard['temp'] = $this->load->view('app/dashboard/temp', NULL, TRUE);
    $dashboard['velocity'] = $this->load->view('app/dashboard/velocity', NULL, TRUE);
    $data['dashboard'] = $this->load->view('app/dashboard/dashboard', $dashboard, TRUE);


    $this->load->view('includes/head');
        $this->load->view('app', $data);
    $this->load->view('includes/jquery');
    }
}

所以最终输出就是这样：

Unexpected token < in JSON at position 0(…)

我不知道为什么帖子会返回整个HTML，我将我的数据作为对象发布，我该怎么办？

Answer 1

数据帖子包含JSON对象，你得到了一个像这样的对象元素：

SELECT date, amount,
AVG(amount) OVER(ORDER BY date ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT
ROW) AS AvAmount
FROM a
ORDER BY date

Answer 2

1）您必须重新检查此变量中的内容

data: {data: data},

2）你已经设置了

contentType: 'application/json'

所以你必须以JSON格式返回内容，并且还应该在响应页面中将内容类型设置为JSON

$this->output
->set_content_type('application/json')
->set_output(json_encode($_POST));

AJAX POST到CodeIgniter控制器

2 个答案: