Question

我正在尝试解析.obj文件，我将文件解析并分别存储在vec3和int向量中。

然而，当我尝试通过使用面链接一切来创建我的aitVertex结构以对应顶点和法线时，我得到以下“std :: out_of_range在内存位置”。

以下是相关代码：

bool aitMesh::loadFromObj(std::string path)
{
//Setup vars etc...
//std::vector<float> tempVertices;
//std::vector<float> tempNormals;
float Vertex[3];
float Normal[3];
int Index[6];

std::vector<glm::vec3> tempVertices;
std::vector<glm::vec3> tempNormals;
std::vector<int> tempIndices;


if (name == "v")
{
    //sscanf_s matches a sequence of non-whitespace characters
    //line.c_str returns a pointer to an array that contains a string..
    //in this case and stores in Vertex[1,2,3]
    sscanf_s(line.c_str(), "%*s %f %f %f", &Vertex[0], &Vertex[1], &Vertex[2]);
    std::cout << "Line: " << line << "\n";
    std::cout << "Name: " << name << "\n";

    //Adds to tempVertices Array
    //tempVertices.push_back(Vertex[0]);
    //tempVertices.push_back(Vertex[1]);
    //tempVertices.push_back(Vertex[2]);

    tempVertices.push_back(glm::vec3(Vertex[0], Vertex[1], Vertex[2]));
    continue;
}
if (name == "vn")
{
    sscanf_s(line.c_str(), "%*s %f %f %f", &Normal[0], &Normal[1], &Normal[2]);
    std::cout << "Line: " << line << "\n";
    std::cout << "Name: " << name << "\n";

    //tempNormals.push_back(Normal[0]);
    //tempNormals.push_back(Normal[1]);
    //tempNormals.push_back(Normal[2]);

    tempNormals.push_back(glm::vec3(Normal[0], Normal[1], Normal[2]));
    continue;
}
if (name == "s")
{
    continue;
}
if (name == "f")
{
    sscanf_s(line.c_str(), "%*s %d//%d %d//%d %d//%d", &Index[0], &Index[1], &Index[2], &Index[3], &Index[4], &Index[5]);
    std::cout << "Line: " << line << "\n";
    std::cout << "Name: " << name << "\n";

    tempIndices.push_back(Index[0]);
    tempIndices.push_back(Index[1]);
    tempIndices.push_back(Index[2]);
    tempIndices.push_back(Index[3]);
    tempIndices.push_back(Index[4]);
    tempIndices.push_back(Index[5]);

}
    for (int i = 2; i <= tempIndices.size(); i++)
    {
        if (i % 2 == 0)
        {
            vertices.push_back(aitVertex(tempVertices.at(tempIndices[i-2]), tempNormals.at(tempIndices[i-1])));
        }
    }

我的程序正在打破的行是

vertices.push_back(aitVertex(tempVertices.at(tempIndices[i-2]), tempNormals.at(tempIndices[i-1])));

我认为问题出现在我引用tempIndices的时候，因为当我尝试打印tempIndices[i-2]时，它会打印出来，因为它应该...... 我只是错误地引用它吗？

Answer 1

我真的不明白你的代码。它仍然不是MCVE（请阅读链接！）。但是，可能导致错误的原因是您只在name的一个特定情况下填充每个向量：

name == "v"
    tempVertices gets populated
name == "vn" 
    tempNormals gets populated
name == "f" 
    tempIndices gets populated
and then...
    you access all three vectors (if tempIndices.size() >= 2)

因此，至少在name == "f"的情况下，您可以访问超出向量大小的向量索引。

continue应该做什么？ continue只在循环中有意义，我不明白你为什么把它放在那里。这可能还不是真正的代码吗？

在另一个向量中引用向量索引时出错：'std :: out_of_range在内存位置'

1 个答案: