二进制到十六进制转换器

时间:2016-10-03 11:59:12

标签: python binary hex

我编写了一个代码来尝试将4位二进制数转换为十六进制数。唯一的问题是,当我输入一个以'1'开头的值时,它会产生转换,而如果我输入一个以'0'开头的值,它就不起作用。有什么帮助吗?

print ("""Here's how the program will work. You need to get your binary number ready.
        if it is 8 bit, split it into four, because thats how hexadecimal works. Make sure all your conversions
        are slip into '4' bits like this:
        01001101 will turn into:
        0100 ,and then 1101""")
time.sleep(6)
print ("""So, for example, the program will ask you for your binary number. Like this:
        Enter your binary number here:
        Then you put in your number, like this:
        Enter your binary number here: 0100
        Lastly, the program will give you your hexadecimal number, then ask you if you would
        like to do another conversion in this area, or end program.""")
time.sleep(6)
HEXADECIMAL = int(input("Please enter your binary number here:   "))                         
if HEXADECIMAL == 0000:
    print ("Your hexadecimal value is 0")
if HEXADECIMAL == 0001:
    print ("Your hexadecimal value is 1")
if HEXADECIMAL == 0010:
    print ("Your hexadecimal value is 2")
if HEXADECIMAL == 0011:
    print ("Your hexadecimal value is 3")
if HEXADECIMAL == 0100:
    print ("Your hexadecimal value is 4")
if HEXADECIMAL == 0101:
    print ("Your hexadecimal value is 5")
if HEXADECIMAL == 0110:
    print ("Your hexadecimal value is 6")
if HEXADECIMAL == 0111:
    print ("Your hexadecimal value is 7")
if HEXADECIMAL == 1000:
    print ("Your hexadecimal value is 8")
if HEXADECIMAL == 1001:
    print ("Your hexadecimal value is 9")
if HEXADECIMAL == 1010:
    print ("Your hexadecimal value is A")
if HEXADECIMAL == 1011:
    print ("Your hexadecimal value is B")
if HEXADECIMAL == 1100:
    print ("Your hexadecimal value is C")
if HEXADECIMAL == 1101:
    print ("Your hexadecimal value is D")
if HEXADECIMAL == 1110:
    print ("Your hexadecimal value is E")
if HEXADECIMAL == 1111:
    print ("Your hexadecimal value is F")

您可以尝试运行此代码并从例如0110开始,但它不会转换。有什么帮助吗?

3 个答案:

答案 0 :(得分:0)

当你输入一个以前导0开头的整数时,python将它解释为在base 8中:

a = 0110
print a

将输出

72

因此,请在输入中删除前导0,或者在投射int()之前删除它们

答案 1 :(得分:0)

您不必使用if/else语句加时。有一种很酷的方式可以在python中使用int(),如果使用字符串,int()函数可以直接将它转换为任何基础。

HEXADECIMAL = str(input())

base = 16 # for Hex and 2 for binary
msg = "Your hexadecimal value is"
print (msg, int(HEXADECIMAL, base))

这将为你做到。但是如果你想坚持使用你的方法,你应该在二进制文件之前添加0b 0b0010并执行操作,前导零是非法的,0010是非法的。

答案 2 :(得分:-1)

替换,

HEXADECIMAL = int(input("Please enter your binary number here:   ")) 

用,

temp = input("Please enter your binary number here:   ")                       
HEXADECIMAL = int (temp)

如果出现错误,请删除睡眠时间。