我没有找到使用JPA(EclipseLink)从PostgreSQL映射JSON和JSONB数据类型的方法。是否有人使用这种数据类型与JPA,并可以给我一些工作示例?
答案 0 :(得分:21)
所有答案都帮助我达到了为JPA做好准备的最终解决方案,而不是EclipseLink或Hibernate。
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.IOException;
import javax.json.Json;
import javax.json.JsonObject;
import javax.persistence.Converter;
import org.postgresql.util.PGobject;
@Converter(autoApply = true)
public class JsonConverter implements javax.persistence.AttributeConverter<JsonObject, Object> {
private static final long serialVersionUID = 1L;
private static ObjectMapper mapper = new ObjectMapper();
@Override
public Object convertToDatabaseColumn(JsonObject objectValue) {
try {
PGobject out = new PGobject();
out.setType("json");
out.setValue(objectValue.toString());
return out;
} catch (Exception e) {
throw new IllegalArgumentException("Unable to serialize to json field ", e);
}
}
@Override
public JsonObject convertToEntityAttribute(Object dataValue) {
try {
if (dataValue instanceof PGobject && ((PGobject) dataValue).getType().equals("json")) {
return mapper.reader(new TypeReference<JsonObject>() {
}).readValue(((PGobject) dataValue).getValue());
}
return Json.createObjectBuilder().build();
} catch (IOException e) {
throw new IllegalArgumentException("Unable to deserialize to json field ", e);
}
}
}
答案 1 :(得分:5)
编辑:我现在看到这几乎是Hibernate
依赖的。但也许你可以找到类似于EclipseLink
..
我只是添加我所拥有的答案,它来自另一个SO答案,但无论如何......这会将jsonb
映射到Google JsonObject
的{{1}},但你可以如果需要,将其更改为其他内容。要更改为其他内容,请更改gson
,nullSafeGet
和nullSafeSet
方法。
deepCopy
要使用此功能,请执行以下操作:
public class JsonbType implements UserType {
@Override
public int[] sqlTypes() {
return new int[] { Types.JAVA_OBJECT };
}
@Override
public Class<JsonObject> returnedClass() {
return JsonObject.class;
}
@Override
public boolean equals(final Object x, final Object y) {
if (x == y) {
return true;
}
if (x == null || y == null) {
return false;
}
return x.equals(y);
}
@Override
public int hashCode(final Object x) {
if (x == null) {
return 0;
}
return x.hashCode();
}
@Nullable
@Override
public Object nullSafeGet(final ResultSet rs,
final String[] names,
final SessionImplementor session,
final Object owner) throws SQLException {
final String json = rs.getString(names[0]);
if (json == null) {
return null;
}
final JsonParser jsonParser = new JsonParser();
return jsonParser.parse(json).getAsJsonObject();
}
@Override
public void nullSafeSet(final PreparedStatement st,
final Object value,
final int index,
final SessionImplementor session) throws SQLException {
if (value == null) {
st.setNull(index, Types.OTHER);
return;
}
st.setObject(index, value.toString(), Types.OTHER);
}
@Nullable
@Override
public Object deepCopy(@Nullable final Object value) {
if (value == null) {
return null;
}
final JsonParser jsonParser = new JsonParser();
return jsonParser.parse(value.toString()).getAsJsonObject();
}
@Override
public boolean isMutable() {
return true;
}
@Override
public Serializable disassemble(final Object value) {
final Object deepCopy = deepCopy(value);
if (!(deepCopy instanceof Serializable)) {
throw new SerializationException(
String.format("deepCopy of %s is not serializable", value), null);
}
return (Serializable) deepCopy;
}
@Nullable
@Override
public Object assemble(final Serializable cached, final Object owner) {
return deepCopy(cached);
}
@Nullable
@Override
public Object replace(final Object original, final Object target, final Object owner) {
return deepCopy(original);
}
}
此外,您需要设置方言以表明public class SomeEntity {
@Column(name = "jsonobject")
@Type(type = "com.myapp.JsonbType")
private JsonObject jsonObject;
= JAVA_OBJECT
:
jsonb
答案 2 :(得分:2)
我认为我发现了一个类似于Hibernate的EclipseLink用户类型。
http://www.eclipse.org/eclipselink/documentation/2.6/jpa/extensions/annotations_ref.htm#CHDEHJEB
您必须创建一个实现org.eclipse.persistence.mappings.converters.Converter
的类并为您进行转换,然后在您使用该类型的每个字段上使用@Convert
注释。