Question

我有这样的事情：

let user = [
{
    name: "step-one",
    values: {companyName: "Name", address: "company address"}
},
{
    name: "step-two",
    values: {name: "User", mobile: 0123}
},
{
    name: "step-three",
    values: [
              {file: "companyLogo", values: {active: true, fileName: "some name"}},
              {file: "avatar", values: {active: true, fileName: "file name"}}
            ]
}
]

我想只获取值并将它们放入一个新对象中。因此，像：

let wantedResult = {
    companyName: "Name",
    address: "company address",
    name: "User",
    mobile: 0123,
    files: [
            {file: "companyLogo", values: {active: false, fileName: "some name"}},
            {file: "avatar", values: {active: false, fileName: "file name"}}
        ]
};

我有什么建议吗？

Answer 1

你可以试试这个！

let user = [{
  name: "step-one",
  values: {
    companyName: "Name",
    address: "company address"
  }
}, {
  name: "step-two",
  values: {
    name: "User",
    mobile: 0123
  }
}, {
  name: "step-three",
  values: [{
    file: "companyLogo",
    values: {
      active: true,
      fileName: "some name"
    }
  }, {
    file: "avatar",
    values: {
      active: true,
      fileName: "file name"
    }
  }]
}]

var wantedResult = Object.assign({}, user[0].values, user[1].values, {files: user[2].values})
console.log(wantedResult)

Answer 2

因为文件数组而有点hacky，但我会这样做：

var wantedResult = user.reduce((result, step) => {
    var values = Array.isArray(step.values) ? { files: step.values } : step.values;
    return Object.assign({}, result, values)
}, {});

当然，它只适用于您提供的那种结构。如果你有更多的对象在＆＃39;值中有一个数组＆＃39;财产，你需要重新考虑这种方法。

Answer 3

第3步与其他人不一致。如果可能，请使其保持一致：values: files: [ { file1_data }, { file2_data } ]。

修复不一致之后，您可以遍历每个步骤并将新属性添加到结果中。

let wantedResult = user.reduce(function(result, spec) {
  Object.keys(spec.values).forEach(function(key) {
     result[key] = spec.values[key];
  });
  return result;
}, {});

如果无法更改第3步，则可以减少干净：

let wantedResult = user.reduce(function(result, spec) {
  if (spec.name === "step-three") {
    result.files = spec.values;
  }
  else {
    Object.keys(spec.values).forEach(function(key) {
       result[key] = spec.values[key];
    });
  }
  return result;
}, {});

如何合并具有不同属性的两个对象

3 个答案: