Question

假设我在数据库中有一个包含60列的表。有人可以告诉我查询以获取表格的每列（60）中所有不同条目的计数。

Cl1     Cl2 Cl3
68722   No  No  No  No  No  Yes Male    No  No
68723   No  Yes No  No  No  Yes FeMale  No  No
68725       No  No  No  No  Yes Male    No  No

如上表所示，假设我有10列（第1列到第10列）

我想要的答案：

Cl2 No =2 , Blank=1

Cl3 No=2,  Yes =1

以及最多10个

请给我一个Sql Server的查询。

Answer 1

UNPIVOT + GROUP BY和COUNT：

SELECT  [Columns],
        Case when [Values] = '' THEN 'Blank' ELSE [Values] END [Values],
        COUNT(Id) as HowMany
FROM (
    SELECT  Id,
            CAST(Cl1 as nvarchar(max)) as Cl1,
            CAST(Cl2 as nvarchar(max)) as Cl2,
            CAST(Cl3 as nvarchar(max)) as Cl3,
            CAST(Cl4 as nvarchar(max)) as Cl4,
            CAST(Cl5 as nvarchar(max)) as Cl5,
            CAST(Cl6 as nvarchar(max)) as Cl6,
            CAST(Cl7 as nvarchar(max)) as Cl7,
            CAST(Cl8 as nvarchar(max)) as Cl8,
            CAST(Cl9 as nvarchar(max)) as Cl9
    FROM YourTable
) as t
UNPIVOT (
    [Values] FOR [Columns] IN ( Cl1, Cl2, Cl3, Cl4, Cl5, Cl6, Cl7, Cl8, Cl9)
) as unpvt
GROUP BY [Columns], [Values]
ORDER BY [Columns]

输出：

Columns Values  HowMany
Cl1     Blank   1
Cl1     No      2
Cl2     No      2
Cl2     Yes     1
Cl3     No      3
Cl4     No      3
Cl5     No      3
Cl6     Yes     3
Cl7     FeMale  1
Cl7     Male    2
Cl8     No      3
Cl9     No      3

你可以把它放在CTE中：

;WITH cte as (
    SELECT  [Columns],
            Case when [Values] = '' THEN 'Blank' ELSE [Values] END + '='+CAST(COUNT(Id) as nvarchar(max)) as HowMany
    FROM (
        SELECT  Id,
                CAST(Cl1 as nvarchar(max)) as Cl1,
                CAST(Cl2 as nvarchar(max)) as Cl2,
                CAST(Cl3 as nvarchar(max)) as Cl3,
                CAST(Cl4 as nvarchar(max)) as Cl4,
                CAST(Cl5 as nvarchar(max)) as Cl5,
                CAST(Cl6 as nvarchar(max)) as Cl6,
                CAST(Cl7 as nvarchar(max)) as Cl7,
                CAST(Cl8 as nvarchar(max)) as Cl8,
                CAST(Cl9 as nvarchar(max)) as Cl9
        FROM YourTable
    ) as t
    UNPIVOT (
        [Values] FOR [Columns] IN ( Cl1, Cl2, Cl3, Cl4, Cl5, Cl6, Cl7, Cl8, Cl9)
    ) as unpvt
    GROUP BY [Columns], [Values]
)

SELECT DISTINCT 
            [Columns] +' '+     
            STUFF((
            SELECT ';'+HowMany
            FROM cte
            WHERE c.[Columns] = [Columns]
            FOR XML PATH('')
            ),1,1,'') as [Values]
FROM cte c

输出：

Values
Cl1 Blank=1;No=2
Cl2 No=2;Yes=1
Cl3 No=3
Cl4 No=3
Cl5 No=3
Cl6 Yes=3
Cl7 FeMale=1;Male=2
Cl8 No=3
Cl9 No=3

Sql Query用于获取表的每列中不同条目的计数

1 个答案: