我正在尝试按钮点击计数,如果.kisi-sayi-text
值为= 0,我想添加if else语句不添加但我的代码上没有任何内容
HTML
<div class="count-box yetiskin-count">
<span class="count-text">Yetişkin:</span>
<span class="kisi-down"></span>
<span class="kisi-sayi-text">1</span>
<span class="kisi-up"></span>
</div>
JQUERY
$('.yetiskin-count > .kisi-up').on("click",function(){
var topParents = $(this).parents(".yetiskin-count"),
kisiSayiText = topParents.find(".kisi-sayi-text"),
kisiSayiNumber = kisiSayiText.html(parseInt($(".kisi-sayi-text").html())+1);
if(kisiSayiNumber<0){
return false;
}
});
答案 0 :(得分:0)
请替换此行
kisiSayiNumber = kisiSayiText.html(parseInt($(".kisi-sayi-text").html())+1);
与
kisiSayiNumber = kisiSayiText.html(parseInt($(".kisi-sayi-text").text())+1);
我将以您想要的方式开始添加
答案 1 :(得分:0)
您遇到的问题不在.kisi-up
点击事件中,您应该查看.kisi-down
点击处理程序,因为它处理减法,因此它会在达到0时停止减去。
$('.yetiskin-count > .kisi-up').on("click",function(){
var topParents = $(this).parents(".yetiskin-count"),
kisiSayiText = topParents.find(".kisi-sayi-text"),
kisiSayiNumber = parseInt($(".kisi-sayi-text").html());
kisiSayiText.html(kisiSayiNumber + 1);
});
$('.yetiskin-count > .kisi-down').on("click",function(){
var topParents = $(this).parents(".yetiskin-count"),
kisiSayiText = topParents.find(".kisi-sayi-text"),
kisiSayiNumber = parseInt($(".kisi-sayi-text").html());
if(kisiSayiNumber <= 0){
return false;
}
kisiSayiText.html(kisiSayiNumber - 1);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="count-box yetiskin-count">
<span class="count-text">Yetişkin:</span>
<span class="kisi-down"><</span>
<span class="kisi-sayi-text">1</span>
<span class="kisi-up">></span>
</div>
比较一下:
$('.yetiskin-count > .kisi-up').on("click",function(){
var topParents = $(this).parents(".yetiskin-count"),
kisiSayiText = topParents.find(".kisi-sayi-text"),
kisiSayiNumber = kisiSayiText.html(parseInt($(".kisi-sayi-text").html())+1);
// kisiSayiNumber is a jQuery object, not a number so there is no point comparing it with 0
if(kisiSayiNumber<0){
return false;
}
});
用这个:
$('.yetiskin-count > .kisi-up').on("click",function(){
var topParents = $(this).parents(".yetiskin-count"),
kisiSayiText = topParents.find(".kisi-sayi-text"),
kisiSayiNumber = parseInt(kisiSayiText.html());
// if the current running number is less than or equal to 0 then don't add
if (kisiSayiNumber <= 0)
return false;
kisiSayiText.html(kisiSayiNumber + 1);
});
答案 2 :(得分:0)
问题出在您的<span class="kisi-up"></span>
中..尝试输入一些数据。
例如
<span class="kisi-up">Click Me</span>
因为您无法点击范围kisi-up
$('.yetiskin-count > .kisi-up').on("click",function(){
var topParents = $(this).parents(".yetiskin-count"),
kisiSayiText = topParents.find(".kisi-sayi-text"),
kisiSayiNumber = kisiSayiText.html(parseInt($(".kisi-sayi-text").html())+1);
if(kisiSayiNumber<0){
return false;
}
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="count-box yetiskin-count">
<span class="count-text">Yetişkin:</span>
<span class="kisi-down"></span>
<span class="kisi-sayi-text">1</span>
<span class="kisi-up">Click Me</span>
</div>
&#13;
答案 3 :(得分:0)
$('.yetiskin-count > .kisi-up').on("click",function(){
var topParents = $(this).parents(".yetiskin-count");
var kisiSayiText = topParents.find(".kisi-sayi-text");
if($(".kisi-sayi-text").html()<=0){
return false;
};
kisiSayiNumber = kisiSayiText.html(parseInt($(".kisi-sayi-text").html())+1);
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="count-box yetiskin-count">
<span class="count-text">Yetişkin:</span>
<span class="kisi-down"></span>
<span class="kisi-sayi-text">1</span>
<span class="kisi-up">click here</span>
</div>
&#13;
喜 您需要在span标记中包含一些内容才能单击并确保包含JQuery库。您可以运行代码段来检查功能。 我希望这能解决你的问题。快乐的编码!!!