基本上我有三个名为class,rooms,hostel的表。这是我的表
类
id name daily_rent mon_rent facilities
11 reservation 200 3000 reservation
23 per1 100 1000 per1
24 per2 100 1000 per2
25 pamba1 100 1000 pamba1
26 pamba2 100 1000 pamba2
我的桌子房间看起来像这样
id rm_number capacity bed_no class hostel is_vaccant
34 1 5 1A,1B,1C,1D,1E 23 7 1
35 2 4 2A,2B,2C,2D 24 7 1
36 3 4 3A,3B,3C,3D 25 10 0
37 4 6 4A,4B,4C,4D,4E,4F 26 10 0
38 5 3 5A,5B,5C 23 7 1
39 6 8 6A,6B,6C,6D,6E,6F,6G,6H 25 10 1
我的宿舍表看起来像这样
id user_id name type place address phone username password
7 78 periyar Girls tirur malappuram periyar periyarhostel
10 81 pamba Boys tirur malappuram 04942569878 pamba pambahostel
当我使用我的代码时
控制器
public function view_vaccancy()
{
$data['active_mn'] = 'view_vaccancy';
if( ! $this->ion_auth->logged_in() || !$this->ion_auth->is_admin())
{
redirect('login');
}
$data['class'] = $this->admin_model->get_all_vaccancy_list()->result();
$data1=array();
foreach ($data['class'] as $row)
{
$bed = $this->admin_model->bed_by_class_admin($row->id)->row();
$res = $this->admin_model->get_admitted_room_admin($row->id);
$data1[] = $bed->capacity-$res;
}
$data['available'] = $data1;
$data['bed'] = $bed = $this->admin_model->bed_by_class_admin($row->id)->row();
$data['form_url'] = '';
$data['plc_hold'] = 'Name / ID';
$this->load->view('admin/view_vaccancy',$data);
}
我的模型看起来像这样
public function get_all_vaccancy_list()
{
$this->db->select('class.*,rooms.class,hostel.name as h_name');
$this->db->join('rooms','class.id=rooms.class','left outer');
$this->db->join('hostel','hostel.id=rooms.hostel');
$query=$this->db->get('class');
return $query;
}
我即时得到我的输出
SI no Hostel Class Total Seat No. of Vaccancy
1 periyar per1 12 8
2 periyar per2 12 4
3 pamba pamba1 12 8
4 pamba pamba2 12 2
5 periyar per1 12 8
6 pamba pamba1 12 8
但我必须得到这样的
SI no Hostel Class Total Seat No. of Vaccancy
1 periyar per1 12 8
2 periyar per2 12 4
3 pamba pamba1 12 8
4 pamba pamba2 12 2
我的问题是模型任何猜测,以提前解决此问题
答案 0 :(得分:1)
您需要对其进行分组。
$this->db->group_by('hostel, class');