Question

我想在软键盘弹出窗口中隐藏操作栏。我使用以下代码的代码来获得结果。但当我想回去时，应用程序崩溃了。我已经包含在哪一行我也得到了错误。请指导我完成这个。

提前致谢。

private void createView（）{

    mRootView.getViewTreeObserver().addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() {

        @Override
        public void onGlobalLayout() {

            Rect rect = new Rect();
            //rect will be populated with the coordinates of your view that area still visible.

            mRootView.getWindowVisibleDisplayFrame(rect);
            int heightDiff = mRootView.getRootView().getHeight() - (rect.bottom - rect.top);

            if (heightDiff > 100) {

                // if more than 100 pixels, its probably a keyboard...
                //keyboard visible
                mBinding.healthRecordContainer.setVisibility(View.GONE);
                ((AppCompatActivity) getActivity()).getSupportActionBar().hide();

            } else {

                //keyboard not visible
                mBinding.healthRecordContainer.setVisibility(View.VISIBLE);
                ((AppCompatActivity) getActivity()).getSupportActionBar().show(); // app crashes
            } //java.lang.NullPointerException
        }
    });
}

Answer 1

在您宣布活动的清单中只做一件事。例如。

<activity
            android:name=".Your Activity here"
            android:windowSoftInputMode="stateVisible|adjustResize"
            >
        </activity>

Answer 2

您可以使用以下代码。然后app不会崩溃。

Activity activity = getActivity();

if (activity instanceof ActionBarActivity) {

    ActionBarActivity actionBarActivity = (ActionBarActivity) activity;

    ActionBar actionBar = actionBarActivity.getSupportActionBar();

    if (actionBar != null) {
        actionBar.hide();
    }
}

在片段中的软键盘弹出窗口中隐藏操作栏

2 个答案: